The highest barrier that a projectile can clear is 18.4 m, when the projectile is launched at an angle of 15.0° above the horizontal. What is the projectile's launch speed?
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- In frustration, Jimmy Alapag threw the ball with a velocity of 20.0 m/s at an angle of 45° above thehorizontal. What was the maximum range that the ball reached?A lizard kicks a ball with an initial velocity of 10 m/s at an angle of 35º with the horizontal. What is the maximum height of the ball?A tennis player hits the tennis ball at a distance of 10 m from the net. The ball is hitat a height of 1.2 m above ground so that it starts moving with a velocity of 30 m/s ina horizontal direction (parallel to the ground). The height of the net is 90 cm. What is the angle the tennis player has to hit the ball so it will just clear thenet?
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- A ball is thrown from the ground with a speed of 50 m/s at an angle of 35o above thehorizontal. If we neglect air resistance,a) What maximum height does the ball reach?b) How far from where it is thrown will the ball land?A soccer player kicks a ball 30.0 meters toward the goal, the ball just passes over the goal at 2.4 meters above ground at an angle of 40degrees. What is the initial speed of the ball if it just passes over the goal?include FBD A stone is thrown upward from the top of the building at an angle of 30owith the horizontal and an initial velocity of 20 m/s. If the height of thebuilding is 45 m, how long will the stone be in flight? What is the totalhorizontal distance traveled by the stone?
- The initial speed of a tennis ball is 57.5 m/s and the launch angle is ?i = 16°. Neglect air resistance.Question 1) What is the maximum height, h, of the tennis ball? in mQuestione 2) What is the range, R, of the tennis ball? in m info given: what angle results in the greatest height=90 For this 90° angle, the horizontal component of velocity is zero, so the initial velocity is completely in the vertical direction, resulting in greatest height Kato tries substituting ty,max for t, 0 for yi, and h for yf, and gets h = vi2 sin2 ?i 2g When ?i = 90°, sin2 ?i is maximum, so h is maximum what angle results in the maximum horizontal range=45° I substituted 2vi sin ?i g into the expression for the horizontal component of velocity, (vi cos ?i)t, and got R = 2vi2 sin ?i cos ?i g when ?i = 45°, 2?i = 90°, and sin 90° = 1, which is its maximum value.Launch a tennis ball at 100 mph, from the ground level. You get a maximum height of 50 m. Findthe initial launch angle.An arrow is shot from a height of 1.8 m toward a cliff of height H. It is shot with a velocity of 26 m/s at an angle of 60º above the horizontal. It lands on the top edge of the cliff 5.24 s later. What is the height of the cliff?