The distance “s” meters from a fixed point of a vehicle traveling in a straight line with constant acceleration “a” is given by the formula s = ut + ½ at2 where “u” is the initial velocity in m/s, and “t”, the time in seconds. Given s = 42 m when t = 2 seconds and s = 144 m when t = 4 seconds. a. Determine the initial velocity. b. Determine the acceleration c. Determine the distance traveled after 3 seconds

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Q: 1. Which of the following pairs of graphs shows the displacement versus time and the velocity versus…

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A: Given: Time at which Larry leaves home = 9:05  Time at which the Larry reaches Lamppost = 9:10

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Q: Problem 1: An object is thrown straight up with an initial velocity of 17 m/s. Part (a) How high…

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Q: 3. A car is moving with constant speed of 80 km h when suddenly the driver sees a cat 50 m straight…

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Q: Fundamentals of Kinematics  A.) Consider a particle moving in a straight line and assume that it's…

A: The position of a particle in a straight line is given by the equation as follows : x=6t2 - t3…

Q: 1. A man drives his Ford Territory down a straight road at 5.2km at 40kph then he ran out of gas.…

A: Given DataD1=5.2kmV1=40kph=40km/hrD2=2.5kmT2=30min

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Q: .Leo traveled 25.0km from their house to a shopping mall to meet a friend .Upon reaching the…

A: length of path from house to mall = 25 km length of path from mall to house = 25 km ∆t = 0.75 h

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Q: A cyclist rides 8.0 km east for 35 minutes, then he turns and heads west for 10 minutes and 3.7 km.…

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Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –