Suppose that income causes health in the following specific manner: h = 2 + .25y and that health aids income as follows: y = 6 + 3h Based on this information, answer the following: a. Graph the two functions on the (y, h) graph and show the equilibrium (y on the x axis and h on they axis). b. Derive the equilibrium pair (y*, h*) and show on the graph above. 7 c . Now suppose that access to health is segmented by income in this country so that: h= 2 + .25y for all y < = 50 and h = 4 + .25y for all y > 50 Derive the new equilibrium and redraw the graphs again in the (y, h) space and depict the old and new equilibria.

Microeconomic Theory
12th Edition
ISBN:9781337517942
Author:NICHOLSON
Publisher:NICHOLSON
Chapter4: Utility Maximization And Choice
Section: Chapter Questions
Problem 4.2P
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Suppose that income causes health in the
following specific manner: h = 2.25y
and that health aids income as follows: y
= 6 + 3h Based on this information,
answer the following: a. Graph the two
functions on the (y, h) graph and show
the equilibrium (y on the x axis and h on
the y axis). b. Derive the equilibrium pair
(y*, h*) and show on the graph above. 7 c
Now suppose that access to health is
segmented by income in this country so
that: h= 2 + .25y for all y < = 50 and h
= 4 + .25y for all y > 50 Derive the new
equilibrium and redraw the graphs again
in the (y, h) space and depict the old and
new equilibria.
Transcribed Image Text:Suppose that income causes health in the following specific manner: h = 2.25y and that health aids income as follows: y = 6 + 3h Based on this information, answer the following: a. Graph the two functions on the (y, h) graph and show the equilibrium (y on the x axis and h on the y axis). b. Derive the equilibrium pair (y*, h*) and show on the graph above. 7 c Now suppose that access to health is segmented by income in this country so that: h= 2 + .25y for all y < = 50 and h = 4 + .25y for all y > 50 Derive the new equilibrium and redraw the graphs again in the (y, h) space and depict the old and new equilibria.
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