Suppose an electron (q = - e= -1.6× 10¬19 c,m=9.1×10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U 1 mv² and using the formula for potential energy above, we arrive at an equation for speed: Since K= v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

Suppose an electron (q = - e= -1.6× 10¬19 c,m=9.1×10¬31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K= -U 1 mv² and using the formula for potential energy above, we arrive at an equation for speed: Since K= v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter26: Electric Potential

Section: Chapter Questions

Problem 67PQ: A charged particle is moved in a uniform electric field between two points, A and B, as depicted in...

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