Suppose a student conducted an experiment similar to Experiment 3 using a green sports drink mix, preparing the solutions the same way. The green sports drink mix contains Yellow 5 dye and Blue 1 dye, but not Red 40 dye. At the Amax for the Yellow 5 dye, 420 nm, the student measured an absorbance of 0.471. At the Amax for the Blue 1 dye, 620 nm, the student measured an absorbance of 0.269. What is the concentration of the Yellow 5 dye and the concentration of the Blue 1 dye in the stock solution of the green sports drink? concentration of Yellow 5 dye: concentration of Blue 1 dye: mM mM What is the mass of each dye in the 5.00 g sample of green sports drink mix? The molar mass of Yellow 5 dye is 534.36 g/mol. The molar mass of Blue 1 dye is 792.85 g/mol. mass of Yellow 5 dye: go

Suppose a student conducted an experiment similar to Experiment 3 using a green sports drink mix, preparing the solutions the same way. The green sports drink mix contains Yellow 5 dye and Blue 1 dye, but not Red 40 dye. At the Amax for the Yellow 5 dye, 420 nm, the student measured an absorbance of 0.471. At the Amax for the Blue 1 dye, 620 nm, the student measured an absorbance of 0.269. What is the concentration of the Yellow 5 dye and the concentration of the Blue 1 dye in the stock solution of the green sports drink? concentration of Yellow 5 dye: concentration of Blue 1 dye: mM mM What is the mass of each dye in the 5.00 g sample of green sports drink mix? The molar mass of Yellow 5 dye is 534.36 g/mol. The molar mass of Blue 1 dye is 792.85 g/mol. mass of Yellow 5 dye: go

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Caffeine, C8H10O2N4 H2O (MW = 212.2 g/mol) has been shown to have an average absorbance of 0.644 for a concentration of 1.783 mg per 100 mL at 272 nm. A sample of 3.658 g of a soluble coffee product was mixed with water to a volume of 500 mL and a 25 mL aliquot was transferred to a flask containing 25 mL of 0.1 M H2SO4. This was subjected to the prescribed clarification treatment and made up to 500 mL. A portion of this treated solution showed an absorbance of 0.666 at 272 nm. Assumbe b = 1.0 cm. Calculate the % caffeine (w/w) in the sample.
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Macmillan Learning Suppose a student conducted an experiment similar to Experiment 3 using a green sports drink mix, preparing the solutions the same way. The green sports drink mix contains Yellow 5 dye and Blue 1 dye, but not Red 40 dye. At the Amax for the Yellow 5 dye, 420 nm, the student measured an absorbance of 0.187. At the Amax for the Blue 1 dye, 620 nm, the student measured an absorbance of 0.255. What is the concentration of the Yellow 5 dye and the concentration of the Blue 1 dye in the stock solution of the green sports drink?
Bromophenol blue= max 600 concentration (M) of the original solution =10.0 mg/L absorbance solution 1 = 0.20 solution 2 = 0.43 %3D %3D solution 3 = 0.66 solution 4 = 0.93 %3D solution 5 = 1.10 I need the concentration (M) in all the solution
Suppose that a solution has an absorbance of 0.250 at a wavelength of 450 nm. If the concentration of the solution is 22 μM, what is the value of the molar absorptivity? The data were taken with a standard 1-cm cuvette. molar absorptivity in (L cm^−1 mol^-1):
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