Saline solutions (NaCl in water) used to deliver intravenous drugs are 0.890 % (w/v). What mass of NaCl is found in 500. mL of such a solution?
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- Exactly 1.00 grams of granular table salt was dissolved in deionized water up to 500 mL. An aliquot of 20 mL was titrated with AgNO3 (T = 8244 mg/mL) and consumed 46.60 mL to reach end point. If the impurities are just water, calculate the percent Moisture. Ans in 1 sig figure.The toxicity of DDT (C14H9Cl5) led to a ban on its use in the United States in 1972. Determinations of DDT concentrations in groundwater samples from Pennsylvania between 1969 and 1971 yielded the following results: Location Sample Size Mass of DDT Orchard 253 mL 0.0310 mg Residential 1.77 L 0.0350 mg Residentialafter a storm 51.5 mL 0.570 mg Express these concentrations in millimoles per liter. Orchard= ___mmol/l Residental=___ mmol/l Residential after a storm=___ mmol/LBeaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =
- ii During the standardization of NaOH , an air bubble was present in the tip of the buret when making the initial volume reading, but was not present when making the final volume reading. Would this affect the final calculations of molarity of NaOH? If so, how? Explain. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). 14px A In ... BIUS Paragraph Arial150 140 130 120 110 100 NaNO3 90 80 70 60 NH&C KCI Naci 50 40 30 20 KCIO3. 10 Cez(SOA)3 0 10 20 30 40 50 60 70 80 90 100 Temperature ('C) EONX NH37 Grams of soluteHow many grams of solute are in 2000. mL of a 5.00 ppm solution ? The concentration will always be the conversion factor. Like %m/m, ppm and related concentrations are in g/ml. 5.00 ppm means 5.00 g in a million mL, or 5.00 g/106 mL, or 5.00 g/mL x 106. g mL)(- -) = 1.00 x mL a. 0.00 b. 1.00 С. 2.00 d. 3.00 е. 4.00 f. 5.00 g. 6.00 h. 8.00 i. 10.00 j. 2000 k. 102 I. 103 m. 106 n. 109 0. 1012 р. 102 q. 10-3 r. 10-6 S. 10-9 t. 10-12 и. 108 V. 10-1 w. 101 Х. 30.0 у. О.100 z. 0.200 aа. 20.0 bb. 40.0 СС. 1.33. dd. 0.267
- A 30 mL sample of vinegar is titrated with 39 mL of 0.5 N Sodium Hydroxide. What is the normality of the acetic acid (CH3COOH) in vinegar? Atomic Weights :Sodium - 22.99Oxygen - 15.999Hydrogen - 1.008 Enter numerical value only; round off to 4 decimal places if necessaryWe can measure the concentration of HCl solution by reaction with pure sodium carbonate:Complete reaction with 0.9674 ± 0.0009 g of Na2CO3 (FM 105.9884 ± 0.0007) required 27.35 ± 0.04mL of HCl. Find the molarity of the HCl and its relative and absolute uncertainties. Report themolarity to the correct number of digits. What is the major source of uncertainty in the molarity?A 95.0 wt% solution of ethanol (CH3CH2OH, FM 46.07) in water has a density of 0.804 g/mL. (a) Find the mass of 1.00 L of this solution and the grams ofethanol per liter. (b) What is the molar concentration of ethanol in this solution?
- Fundamentals of Chemistry 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 0 Grams of solute/100g H₂O 0 KI Na2SO47 NaNO3 HCI NH3 Lab Manual KNO3 NaCl gases solids NH4CI KCI KCIO3 SO2 10 20 30 40 50 60 70 80 90 Temperature (°C) Sem-3/2021-22) 100 Page 4 of 8 indan Aim ASExactly 10.00-mL aliquots of a solution containing phenobarbital were measured into 50.00-mL volumetric flasks and made basic with KOH. The following volumes of a standard solution of phenobarbital containing 2.000μg/mL of phenobarbital were then introduced into each flask and the mixture was diluted to volume: 0.000, 0.500, 1.00, 1.50, 2.00 mL. The fluorescence of each of these solutions was measured with a fluorimeter, which gave values of 3.26, 4.80, 6.41, 8.02, 9.56, respectively. a. plot the data. b. derive a least squares equation for the data plotted in (a). c. find the concentration of phenobarbital from the equation in (b). d. calculate a standard deviation for the concentration obtained in (c).Qs/ A 0.2121-g sample of pure Na,C,0, (134.00 g/mol) was t ed with 43.31 mL of KMnO;. What is the normality of the KMnO, solution? The chemical reac- tion is 2MnOj; + 5C,0i + 16H* — 2Mn?* + 10CO, + 8H,O