RA computer vystem has a 4K wod cache rpnied in Mock with four blocks per set, 64 words per block cative manner The number of hits in the SET and WORD fields of the main memory address fomat is
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- Suppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. Supposed also that each block contains 16 bytes. The size of the offset field is 19 bits and the size of the block field is 0.625 bytes.In a dynamic random access memory (DRAM) computer chip, each memory cell chiefly consists of a capacitor for charge storage. Each of these cells represents a single binary-bit value of 1 when its 35-fFfcapacitor (1fF=10^−15F) is charged at 1.5 V, or 0 when uncharged at 0 V. A)When it is fully charged, how many excess electrons are on a cell capacitor's negative plate? B) After charge has been placed on a cell capacitor's plate, it slowly "leaks" off (through a variety of mechanisms) at a constant rate of 0.30 fC/s. How long does it take for the potential difference across this capacitor to decrease by 1.0% from its fully charged value? (Because of this leakage effect, the charge on a DRAM capacitor is "refreshed" many times per second.) Express your answer to two significant figures and include the appropriate units.physcal addresses are 4s ng 4 Ame dat in a cetain compe, te addresses can be translaled without y TLB entries At most how many ditina vid the address translation peh has 12 vld The Translation Look aside Bulfer (TLB)i sine is kB and the word size iby The memory is word addresible. The pe virtual addresses are 64 bea long d th sine is miss?
- The 32-bit number 52AB43FC (in hexadecimal) is stored in abyte-addressable memory starting at physical address FE08 (in hex) using Little-Endian notation. The byte(value ni hexadecimal) stored at theaddress FE0B will beA computer system contains a big endian byte addressable memory system with 8 separate memory modules. Each memory module is 32 bits wide and contains 134217728 cells. Cells within each memory module are numbered 0 through 134217727. a) If the memory employs high order interleaving, what is the 32-bit memory address of cell 1048578 within module 3? b) If the high order interleaved memory uses little-endian instead of big-endian storage order, what is the 32-bit memory address of cell 511 within module 1? c) If the memory employs low order interleaving, what is the 32-bit memory address of byte 1048575 within module 2? Bytes are numbered starting from 0. Express the address in hex. d) What is the main advantage of using low-order interleaved memory compared to using high-order interleaved memory?Show how the decimal value 2019111310 would be stored by byte-addressable machines with 32-bit words, using little endian format and then big endian format. Assume the value starts at address 201916. Draw a diagram of memory and place the appropriate values in the correct (and labeled) memory locations.
- Please if could, typed solution Consider a logical address space of 32 pages of 1024 words each, mapped onto a physical memory of 64 frames. How many bits are there in the logical address? How many bits are there in the physical address?Suppose we have a byte-addressable computer using 2-way set associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 8 bytes, determine the size of the offset field, and show your work.Let's pretend for a moment that we have a byte-addressable computer with 16-bit main memory addresses and 32-bit cache memory blocks, and that it employs two-way set associative mapping. Knowing that each block has eight bytes, please calculate the size of the offset field and provide evidence of your calculations.
- draw memory page table for virtual memory for memory space 32K address space 1024 K with size of page 1KSuppose we have a byte-addressable computer using fully associative mapping with 16-bit main memory addresses and 32 blocks of cache. If each block contains 16 bytes: (a) Determine the size of the offset field. (b) Determine the size of the tag field.I have a little bit problem with my late quiz for computer architecture, I get the answer from my lecturer but I still don't feel fully understand, can I ask for some help: In a computer system, the memory has 32 blocks and the cache has 8 blocks. Assume there is only one word per block with 4 bytes in one word. The reference sequence in terms of word location is 0, 2, 4, 10, 5, 12, 8, 18, 13. If the cache is direct-mapped, how many misses do we have if the cache is initially empty? Can you give the hit or miss for each reference?