Question 4: Consider the figure below, with three links, each with the specified transmission rate and link length. Link 1 -Link 2 +Link 3+ Tranemission rate: 1000 Mbps Link Length: 1 Km Transmission rate: 10 Mops Link Length: 2 Km Transmission rate: 100 Mbps Link Length: 5000 Km Assume a packet length of 8000 bits is transmitted from host to destination. 1. Find the delay on each link for one packet. 2. Find the end to end (host to destination) delay for one packet Consider transmission delays and propagation delays but ignoring queuing delays and processing delays. Formulas: Transmission delay= Length of packet in bits / Transmission rate Propagation delay = distance between two nodes / 3 x 108 m/s Total delay at each link= Transmission delay + Propagation delay
Question 4: Consider the figure below, with three links, each with the specified transmission rate and link length. Link 1 -Link 2 +Link 3+ Tranemission rate: 1000 Mbps Link Length: 1 Km Transmission rate: 10 Mops Link Length: 2 Km Transmission rate: 100 Mbps Link Length: 5000 Km Assume a packet length of 8000 bits is transmitted from host to destination. 1. Find the delay on each link for one packet. 2. Find the end to end (host to destination) delay for one packet Consider transmission delays and propagation delays but ignoring queuing delays and processing delays. Formulas: Transmission delay= Length of packet in bits / Transmission rate Propagation delay = distance between two nodes / 3 x 108 m/s Total delay at each link= Transmission delay + Propagation delay
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
![Question 4: Consider the figure below, with three
links, each with the specified transmission rate and
link length.
+Link 1+
Link 2
+Link 3+
Transmission rate: 1000 Mbps
Link Length: 1 Km
Transmission rate: 10 Mbps
Link Length: 2 Km
Transmission rate: 100 Mbps
Link Length: 5000 Km
Assume a packet length of 8000 bits is transmitted
from host to destination.
1. Find the delay on each link for one packet.
2. Find the end to end (host to destination) delay
for one packet
Consider transmission delays and propagation
delays but ignoring queuing delays and processing
delays.
Formulas:
Transmission delay= Length of packet in bits /
Transmission rate
Propagation delay = distance between two nodes / 3
x 108 m/s
Total delay at each link= Transmission delay +
Propagation delay](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12339970-a001-4b39-b4fe-719545f995a8%2F5b75e072-c123-4fb8-a058-d80579fc7afd%2F0rehfcs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 4: Consider the figure below, with three
links, each with the specified transmission rate and
link length.
+Link 1+
Link 2
+Link 3+
Transmission rate: 1000 Mbps
Link Length: 1 Km
Transmission rate: 10 Mbps
Link Length: 2 Km
Transmission rate: 100 Mbps
Link Length: 5000 Km
Assume a packet length of 8000 bits is transmitted
from host to destination.
1. Find the delay on each link for one packet.
2. Find the end to end (host to destination) delay
for one packet
Consider transmission delays and propagation
delays but ignoring queuing delays and processing
delays.
Formulas:
Transmission delay= Length of packet in bits /
Transmission rate
Propagation delay = distance between two nodes / 3
x 108 m/s
Total delay at each link= Transmission delay +
Propagation delay
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