Q1/ complete the following (?) and check your competition. Sta. B.S. H.I. F.S. Elevation BM1 4.38 10.00M 1 3.04 2.81 5.43 4 6.12 Тр1 2.15 4.11 7.16 5.01 Тр2 7.15 1.29 7 2.16 8 1.19 BM1 8.30 SUN

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A:

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A:

Q: STATIOΝ B.S. F.S. ELEV. (m) BM1 9.08 150 BM1 9.08 TP1-L 12.24 3.73 TP1-H 10.10 1.60 TP2-L 11.04 2.21…

A:

Q: SIT. 2 EI = constant 212KN 7KNM 1.Sm 3m D 1. Sm A 在 a.) VA b.) ME c.) v. Diagram ( Vmax) 2.

A: xc

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Q: STATION B.S. F.S. ELEV. (m) BM1 9.08 150 BM1 9.08 TP1-L 12.24 3.73 ΤΡ1-Η 10.10 1.60 TP2-L 11.04 2.21…

A: Given data in question  Back sight  Fore sight  Elevation of BM To find out  Elevations Note I have…

Q: tivity Time Immediate predecessor 12 7 A 11 A 8 A 6 A 10 B 9 14 D,F 13 E,G 16 H,I ect one: a. 53 b.…

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Q: Tank is 300mm x 300mm Table 12.2 Variable Head Results Trials Head, h₁ (mm) 1 2 3 200 150 100 Head,…

A: Trials Head, h1 (mm) Head, h2 (mm) h1-h2 Time (sec) Actual Q Theoretical Q Cd 1 200 150 1.89…

Q: VII. Data Collection and Analysis Staff Reading (m) Rise Fall RL Remarks Station BS IS FS (m) (m)…

A: To complete the table by rise and fall method

Q: STA BS HI FS ELEVATION BM-A ТР 1 TP 2 1.73 346.50 m 2.50 1.85 2.76 1.05 TP 3 3.15 1.20 BM-B 1.93…

A:

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A: neutral axis from top so neutral axis from bottom=240-100=140mm

Q: S-1 Line S-2 S-3 S-4 Student No. 4 S-1 S-2 N 29°53'21" W N 21°23'01" E N 61°6'01" E N 4°50'01" W…

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Q: The following consecutive staff readings were taken with level and 5m staff at 70 m interval. The…

A: Given, Elevation at first point and last point= 80m and 84.96m

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A: Yes,  The figure is in equilibrium

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Q: AP=120 kPa 2m Sand V ground water table Sand 3m e=0.50 G=2.70 Clay 2.5m Sm 0.60 LI40%

A:

Q: STA BS HI FS IFS ELEV BMa 0.95 125.50m 0 + 00 + 10 3.0 2.3 TP1 3.13 0.64 0 + 22 2.7

A: The elevation is generally the vertical distance from a datum that is the sea level, to a point on…

Q: Exercise For Practice 924 $12 30 50 FV X

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Q: 4. GNEH: watER 250 2m 44m SUめMERCED RECTAN GULAR SURPAOE OF WIDTH W = : (m

A:

Q: Example Q=1000m/d, D.T= 2hr D,= 0.06 mm Pp=1200 kg/m³, µ=1.027×10³ N.s/m? scour=V70%, find L,W,h if…

A: given data:- discharge=1000 m3/day detention time=2 hr density of partical=1200 kg/m3 viscosity of…

Q: Staff Reading (m) Rise Fall RL Remarks Station BS IS FS (m) (m) (m) 100.0 Bench Mark 1.47m 0-53m…

A:

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Q: Determine the force in each member of the truss shown in Fig. 4.20(a) by the method of joints.

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Q: STA BS HI FS IFS ELEV BМ — а 1.24 234.51 m ТР- 1 1.11 3.40 1 + 00 + 25 + 50 + 75 ТР - 2 4.6 2.7 3.6…

A: Height of instrument method HI = elevation + BS elevation = HI - FS

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Q: 1 7-5 m F 12 m Water Parabola BI

A:

Q: Example Q=1000m/d, D.T= 2hr D,=0.06 mm Pp=1200 kg/m2, µ=1.027x103 N.s/m2 -V/70%, find L,W,h if L-4W…

A: Q=1000m3/dDT=2hrdp=0.06mmρ=1200Kg/m3μ=1.027×10-3Ns/m2Vscour=Vh0.7scoir velocity for primary…

Q: 225 P- 8 P;= 10 9;- 18 2 (m) 1 (m) 4.50 (m) 1.50 (m)

A:

Q: \begin{array}{r}3 \frac{4}{5} \\-1 \frac{1}{3} \\\hline\end{array}

A: To find:- Subtraction

Q: Speed Group (ml/h)Number of Vehlcles Observed (N) 15-20 20-25 25-30 9. 30-35 18 35-40 35 40-45 42…

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Q: a -+ a -b b

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A: Given data:- Test reading Trial 1 Reading Trial 2 Reading Trial 3 Reading w = 310 g w = 210 g w…

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.