Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 0 = 35" and 02= 03 = 20°. Calculate the moment that the force, F, exerts about the point A. %3D D. A
Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Given, F= 250 N L = 1.5 m θ1 = 35o θ2 = θ3 = 20o
Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Given data: The magnitude of the force, F = 250 N. Length of each segment, l = 1.5 m. Draw a…
Q: Problem 1 From Fig. P-1, P is directed at an angle a from x-axis and the 200 N force is acting at a…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: F = 250 N Theta 1 = 35° Theta 2 = theta 3 = 20°
Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that cach…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that cach…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Given: Applied load is 250 N. Length of the each segment is 1.5 m.
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Given data: Length of each segment, l = 1.5 m. The magnitude of force applied, F = 250 N. Draw a…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Data given- F = 250 N L = 1.5 m θ1 = 35° θ2 = θ3 = 20°
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Given data Force = 250N Length of each segment = 1.5m θ1= 35 degree θ2 = θ3 = 25 degree
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
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A: Given: AB=BC=CD=1.5m θ1=35°θ2=θ3=20° F=250N Solution: We have to find distance a,b,c to find the…
Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
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Q: B: Find the total moment of force with respect to point (A), for the two forces in next fig. 8m 3m…
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Q: Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each…
A: Data given- F = 250 N θ1 =35° θ = θ3 = 20°
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- Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35° and 02 = 03 = 20°. Calculate the moment that the force, F, exerts about the point A. F B 02 O3 AQ) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts * .about the point A F В C B.Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts .about the point A F C A M = -1042 M = -1055 M = -1050 M = -1046
- Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts * .about the point A F B CA simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 03 = 20 degree. Calculate the moment that the force, F, * .exerts about the point A %3D F D C. B.Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 0, = 35° and 02 = 03 = 20°. Calculate the moment that the force, F, exerts about the point A. F 02 A
- Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 : 35° and 02 = 03 = 20°. Calculate the moment that the force, F, exerts about the point A. F В D 03 A令回 docs.google.com/forms O Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts * .about the point A M = -1050 O M = -1046 M = -1055 M = -1042 O :F1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m bo
- Ql:- For the two force systems shown below, find the following: 1. The resultant force and its directions. 2. The resultant moment about the origin. 3. The resultant moment with respect to line OA shown below. 26 A F,- 300 Ib 4 f 700H 2 ft F S00 Ib 15 in. 8 in. 8 in. to kip 15 in. F2= 20 kip 5 in. F = 25 kip$ Magnitude R= Direction 8 = Three forces act on point : A = 60 N at 135°, B = and C in this diagram to the correct magnitudes and directions. When this has been done correctly the dotted vector will become solid. 50 N at -45° and, C= 75 N at 60° 2. Pick up vectors A, B and C by their tails, and move them into a tip to tail arrangement. When this has been correctly done the resultant R will appear. measured Estimate the magnitude and direction of the resultant Based on this diagram, estimate the magnitude R and direction of the resultant. from the force R using the tip-to-tail method. 1. Move the tips of forces A, B, Submit part Submit partF1 F2 a B C. F4 D FS Consider the following values: a - 25 m; b - 5 m; c - 25 m; d - 5 m; F1 = 3 kN; F2 - 4 kN; F3 - 5 kN; P4 - 6 kN; F5 - 7 kN; a = 30°, 0 = 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 65.8 kN.m )-74.6 kN.m d) 42.9 KN.m e) - 53.7 kN.m f) - 97.1 kN.m b) 82.7 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b) 112.7 KN.m c) 321.6 kN.m d) 88.9 kN.m e) - 138.7 kN.m f) 214.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - $6.7 kN.m b) 111.1 KN.m e) - 254.6 kN.m d) 217.9 kN.m e) - 146.2 kN.m ) 135.3 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 117.8 kN.m b) 182.7 KN.m c)- 281.9 KN.m d) 316.9 kN.m e) - 141.4 kN.m ) 210.1 kN.m 5] What is the moment of the force F2 about point E? a) 111.7 kN.m b) 28.1 kN.m c) 54.6 kN.m d) 93.1 kN.m e) 79.3 kN.m f) 21.3 kN.m