Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive
Part B involves the addition of sodium acetate in the reaction between 2.6- dimethylaniline and chloroacetyl chloride. Why is sodium acetate used in this step? ○ To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so less reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so less reactive To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a stronger nucleophile so more reactive O To quench the side product (HCI) so that it can not protonate aniline. The protonated aniline is a weaker nucleophile so more reactive
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter24: Carboxylic Acids & Derivatives
Section: Chapter Questions
Problem 16CTQ
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