P3: A simply supported beam has a span of 6 m. If the cross section of the beam is as shown below, fe= 35 MPa, and fy = 420 MPa, determine the allowable uniformly distributed service live load on the beam. "5 man 2-20 |-- om 400 mm "5 mm 3-32 -250 mm
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- W 72 EI УБ A For the cantilever beam and loading shown, determine Part 1 (a) the equation of the elastic curve for portion AB of the beam, Part 2 out of 3 (b) the deflection at B, 10 wa 3x² W -2a- B - 16 ax down CMECH 1 ASSIGNMENT 1 y 10k E - 2M 20 k G C 20 k 50 Problem A truss is subjected to the following forces as shown. Determine: (a.) The magnitude of the resultant of the external forces, R (kips). D *Kip (k)-a unit of force, equivalent to 1000 lbs. (Av. AH. Bv) 20 k 15-10 I 25 25 10 15 ft ft ft ft ft In short, solve for the reactions at the supports using the equilibrium equations >Fv, ΣFH, ΣΜ (AH, Av, Bv) F 10 k 15 ft + 10 ft 25 ft BEYA 98 B/s docs.google.com/forms 100 Papertine J MA Papertine Papertine 45 - ls- das #2: For the Simply supa ted beam having the Sechin Shown and londed partially, Find: 1. Draw the bending moment diagram ? 2. Find the value of the maximum bendig moment Mmak 3. Find the value f the maximum bending stress Vmax ال لعة البطم رات المطع الو ضع المكل والحملة ۱. أسم الر البان لعن اوكماو : Mmax sls! e de i ană fic أوجه تعة أ على إ دإما کے ļ Umax KN/m - 20 Cm 4 1 m. 2 m. 1 m. Neutral 40 cm Axis Beam (AB) Beam Cross- Section ت إضافة ملف
- View Policies Current Attempt in Progress The simply supported beam consists of a W460 x 82 structural steel wide-flange shape [E-200 GPa; 1-370 x 10 mm4]. For the loading shown, determine the beam deflection vc at point C. Assume P-62 kN, w - 28 kN/m, LAB - LBC -2.9 m. LCD - 1.9 m. P W TV D C LBC Answer: VCF LAB B mm. LCDHow much service live load, in kN/m, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 45 kN and a service live load of 90 kN. Do not consider moment amplification. Use NSCP 2015. a. b. LRFD. ASD. wt A kN/m mm² W460x144 1.41 18400 472 13.6 283 SECTION tw bf tf Ix Sx mm mm mm mm³ 22.2 726 3080 mm mm mm 199 6.2m W460x144 Sy Ty Zx ly mm mm³ mm 83.6 591 Zy J Cw mmº mm³ mm³ 67.4 3450 906 2440 4230 mmª8. H / The beam shown below has across seclion of channel Shape with width 360mm.and haghs h= loomm, the web thickness ist= 14mm.Deler- Mine ihe Max imum tensile aud Compressive stressin the beam due to unifom Load? 360Mm 3.6KN/M 14m tiom Please Sir 5T CASIC f-991ES PL DATURAL u CALC (-)
- O 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading condition130% v - + 7 Annotate T| Edit Trial expired Unlock Full Version ENGR 263 A A A 4.8 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is a single overhanging beam. Beam AB supports a 500-lb/ft uni- formly distributed floor load on the beam overhang only. Overneia 4 Fr Stee ream (reactions) R. Free-body diagram (negligible weight) Loading conditionE CH2- Resultant paf - Adobe Acrobat Pro Estended Fle Edit View Document Comments Forms Tools Advanced Windew Help 2/87 If the resultant of the two forces and couple M passes through point O, determine M. 150 mm 60° mm 30 M, = M-400x 0.15cos30-320x0.3 0 M = 148 Nm CCW 320 N 160 400 N mm Example : Replace the three forces acting on the bent beam by a single equivalent force R. Specify the distance x from the point O in which the line of action of R passes. 200 N 160 N ahid hamoodi •..
- in simply supported beam shown in fiy. use: Pey- loe sin 4t Yes-4-) %3D Pet) %3D m = 50 per unit length C = 150 EI=65 l0 IL.in? L/2 L/2500 mm 62.5 mm 375 mm 62.5 mm P. Determine the total required number of 20mm bars to be used in two end faces only for the 300mm x 500mm rectangular column shown to support the following loads: Pu = 800 kN Mu = 120 kN-m Use f'c = 20.7 MPa and fy = 413.7 MPa Use 1 ksi = 6.893 MPa %3D 300 mm O O O Oure B 2m2 m C -2 m D 4 m 500 N 700 N 2 of 2 Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. 000 CD DE CG CF FG BC BG DF AG EF AB Submit Provide Feedback Request Answer