Obtain the equilibrium constant for the reaction HCN (aq) ---- H+(aq) +CN- (aq) From the following: HCN(aq) + OH-(aq) ---- CN-(aq) H2O (l), k1= 4.9x10^4 H2O (l) ---- H+(aq) +OH-(aq), k2=1.0x10^-14 Equilibrium constant =

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A: (a)

Q: A solution of sodium chlorite is prepared using 0.38 mol L1 NaOH as the solvent. The pK, of chlorous…

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Q: 2), 3), 4)

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A:

Q: A solution of acetic acid CH3COOH, on a laboratory shelf was of undetermined concentration. If the…

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A: The solution is as follows:

Q: A monoprotic weak acid, HA, dissociates in water according to the reaction HA(aq) + H,O(1) =H,0*(aq)…

A: Given equilibrium Concentration of [HA] = 0.290 M [H3O+]    = 4 × 10-4 M [A-]         = 4.00 × 10-4…

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Q: 1) Calculate the pH of a solution prepared by dissolving 1.60 g of sodium acetate, CH;COONa, in 64.0…

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A: Given that: pH = 0.354 [C8H10N4O2] = 12.063 To find: Kb

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A:

Q: ulate the pH of a solution prepared by dissolving 1.90 g of sodium acetate, CH,COONA, in 85.0 ml of…

A: Given, Mass of Sodium Acetate = 1.90 g Ka of CH3COOH is 1.75×10-5.

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A: Answer is explained below.

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