Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NaOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: (crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 y= -0.0002x + 0.0007 R-0.6565 y--0.4463x - 7.3334 R=0.893 0.0008 0.0006 -6 0.0004 -8 0.0002 -10 2. 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R=1 10000 y= 4000x + 1000 4000 5000 2000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? I Select) What is the order with respect to NaOH? | Select ) What is the value of the averaged rate constant for the reaction above? Give your answer to 3 sig. figs. 1/[crystal orange] [M (crystal orange] (M) 1/(crystal orange] (M In(crystal orange] (M)

EBK A SMALL SCALE APPROACH TO ORGANIC L
4th Edition
ISBN:9781305446021
Author:Lampman
Publisher:Lampman
Chapter1: Solubility
Section: Chapter Questions
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Should be 3 answers in total. Will thumbs up!
Next the student conducts two different runs:
In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate
In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate
The following plots were obtained for each of the runs:
[crystal orange] vs time (RUN 1)
In[crystal orange] vs time (RUN 1)
0.0012
0.001
-2
y--0.4463x- 7.3334
y =-0.0002x + 0.0007
R- 0.6565
R = 0.893
0.0008
4
0.0006
-6
0.0004
-8
0.0002
0.0002
-12
time (hr)
time (hr)
1/[crystal orange] vs time (RUN 1)
1/[crystal orange] vs time (RUN 2)
12000
25000
10000
20000
8000
15000
6000
y = 2000x + 1000
R =1
10000
y 4000x + 1000
R =1
4000
2000
5000
time (hr)
time (hr)
Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide.
What is the order with respect to CO?
| Select ]
What is the order with respect to NaOH?
| Select ]
What is the value of the averaged rate constant for the reaction above? Give your answer to 3 sig. figs.
1/(crystal orange] (M)
(crystal orange] (M)
1/lcrystal orange] (M
In(crystal orange] (M)
Transcribed Image Text:Should be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give your answer to 3 sig. figs. 1/(crystal orange] (M) (crystal orange] (M) 1/lcrystal orange] (M In(crystal orange] (M)
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