(Manning equation) (a) Determine the maximum flowrate possible for the creek shown in the figure below if it is not to overflow ontothe floodplain. The creek bed drops an average of 5.11 ft/half-mile of length. (b) Determine the flowrate during a flood if the depth is 8ft.Light brush floodplainClear, straight8 ft4 ft(a) i50 ft7 ftchannel6 ftPasture floodplain-5 ft80 ftft³/s(b) ift³/s8 ft

Step 1: Step 2: Step 3: Step 4:

Answered: (Manning equation) (a) Determine the…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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OTO > ➡ Discharge • Q2/The flood hydrograph upstream of a proposed bridge Time (hr) (ms) location is as follows: 0 1 The values of K and x for this specific channel section are 3 hours and 0.3 respectively. Find the hydrograph at the bridge location and the flood attenuation. Ans// Flood attenuation = 12.56 cms (1 ||| = فلاتر O 2 3 > S 6 7 8 9 إضافة شرح... × 8 14 26 43 35 25 18 15 12 8 mum
PROBLEM 6 Water in a 6-m-wide rectangular channel flows at a rate of 4 m³/s at a depth of 0.6 m. (a) What is the velocity (m/s) of flow upstream of the hump? (b) Is the flow (0.6 m-depth) super-critical or sub-critical? Compute the Froude number. (c) What is the critical depth, Y. (m)? (d) What should be the height, YH (m), of the hump to be installed if we want critical depth to occur? Yc 0.6 m HUMP Profile of channel YH
A rectangular channel section increases in width from 40 ft to 50 ft in a length of 100 ft. The channel slope is 0.1%. If the discharge and the velocity of flow at section 1 are 2950 cfs and 12.8 ft/sec, respectively, determine the depths of flow at sections 1 and 2 and the velocity at section 2. Use the energy principle. Disregard the losses.please show step by step.
Water level exceeds bank-full level, estimate discharge if flood level is 4m & find value of a velocity coefficient. Manning's n- main channel 0.015 flood banks 0.035 14.5 m 15.0 m 14.5 m 1.5 m y = 4 m 10 m 5 m 10 m Compound channel section Sn = 0.001
T t + 1. Flow 3LH 3/2 2. Length = 70 ft 3. Crest height = 60 ft Hydrology HW1// Route the flood hydrograph indicated below through a reservoir. The storage (elevation versus volume) data obtained from the reservoir survey are given. The spillway has the following characteristics: • Flood Routing • Reservoir Routing • HW1// (1 = புர் ||| Prepared by Dr Nabil Al Amery Inflow Time (hr) Flow (cfs) 0 0.4 0.8 1.2 1.6 2 2.4 2.8 3.2 3.6 0 600 2100 2500 1600 950 550 300 80 0 فلاتر O 4th year civil engineering class Storage Date Elevation Storage (ft) (acre ft) 60 61 62 63 64 65 300 330 360 395 430 470 × إضافة شرح... > mum
(b) A channel is to be designed for carrying a discharge of 50 m/s, side slope 0.5:1 and silt factor 1.0. Calculate the longitudinal slope of the channel also.
ARectangular channel have a discharge 2.1 m3/sec Velocity equal 1.3m/sec,if the water depth equal to has the base find the dimensions of channel and the channel slope use n=0.02 / retry to Solve the problem by using the depth egual to dubole the base
Read the question carefully and give me right solution with clear calculations. At a certain location, the depth of flow in a wide rectangular channel (b y ) is 0.75 m. The channel flow rate is 1.6 m3/sec per unit width (Q/b), the bottom slope is 0.004, and Manning’s coefficient is 0.015. Determine the depth of flow 12 m downstream.
Qle: A flow rate of 0.4m ^ 3 /sec is to be carried in an open channel at a velocity of 1.5 m/sec. If the channel cross section is trapezoidal with water depth equal to the width of the channel bottom and side slope of 1:1. Manning roughness coefficient is 0.03. Determine: a) The bottom width b) The channel bed slope
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