Let X. Y and Z be binary strings of same length and X-xo X Z- zo Z1... Z.. A bitwise operation on X and Y is defined as f (X. Y)-Z where z- x, & y. The operation is defined as follows. X. Xa. Y- yo yı.. y... ya and 1. 1. Design a Turing machine T to compute the function f(X. Y). Assume any two characters as separators among the
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A: Transition No Transition 1 q0a□→q0aaRR 2 q0b□→q0bbR 3 q0□□→q1□□LL 4 q1aa→q1aaLN 5…
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A: We need to contruct turing machine. See below step.
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Q: 8 The turing machine is as follows, (1,0,1,2.R), (1,1,0,2.R), (2,0,0,2,L), (2,b,b,1,R), (2,1,b,1.R.)…
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A: Below i have drawn:
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A: The explanation for the question is given below
Q: Draw a turing machine that represents the language L = {an bm cp : n ≥ m > p}
A: Draw a turing machine that represents the language L = {an bm cp : n ≥ m > p}
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- 1. Turing machines may also be used to compute functions. Give a state-transition diagram for a Turing machine that takes as input a binary string w, increments w, and enters the accepting state. For example, on input w = 100111, the Turing machine begins like this: 90 1|0|0|11|1|-|-|-|-|-|- The Turing machine should halt with 101000 on the tape: Jaccept 101000Computer Science Design a Turing machine that computes the function f(w) = wwR, w ∈ {0, 1}+. Consider that I don't want to know any turing machine that accepts L = {wwR , w ∈ {0, 1}+}. I want to know turing machine that calculates the f(w) = wwR, w ∈ {0, 1}+. If I write to the tape 0011 at initial state, I would like to see 00111100 at the end. Could you please draw states with bubbles and show each input transition expicitly. There is not explicit solution in chegg. As a suggestion drawing of https://turingmachine.io/ could be very helpfull.Consider Г={a, b, c,...,z} and ∑={A,B,C,...,Z} Make a suitable machine for the language that takes your name as input in capital letters and output small letters of your name. eg. on giving input SUFYAN it produces sufyan and produce x on all other alphabets Note :- My Name is Sufyan
- Given n points P1(x1, Y1, 21), P2(x2, Y2, z2) ... Pn(In, Yn, žn), implement the function centerPoint() that finds the center point using the following formula: T1+x2+.+ In Y1+Y2+ . + Yn 21+ 22+...+ 2n, C(xe, Ye, Ze) = ( n centerPoint () takes three arguments: a pointer to an array of struct point*, the number of points in the array, and a pointer to struct point center. It then calculates the coordinates of the center point (for all the points in the array) and stores it in struct point center. You may not use any square brackets ([]) in centerPoint(). struct point { float x; float y; float z; }; void centerPoint (struct point** points, int n, struct point* center) { int main (void) { struct point center; struct point* points [100]; setPoints (points, 100);// Dynamically allocates the points // and initi alizes the points centerPoint (points, 100, ¢er); printf ("center point is (%f, %f, %f)\n, center.x, center.y, center.z); return 0;Computer Science 1. Let Σ = {0, 1} be an alphabet.(a) Let w = 101 be a word over Σ. Compute |w|, the length of w.(b) List all of the words in Σ32. Let {a, b, c} be an alphabet. List all of the words in Σ23. Let Σ = {a, b} be an alphabet and let · denote concatenation. Compute (ba · ε) · abb,where ε is the empty word.4. Let Σ = {0, 1} be an alphabet and let L ⊆ {0, 1} ∗ be the language defined as L = {w ∈ {0, 1} ∗ |w = x10y, x, y ∈ {0, 1}∗}. (a) Determine whether 01 ∈ L.(b) Determine whether 0101 ∈ L. 5. Let Σ = {0, 1} be an alphabet and let L ⊆ Σ ∗ be the language consisting of all wordsover Σ that contain the substring 10. Construct a DFA that accepts L. Thank you in advancea. xpress 2. Given A (w, x, y, z) = (w + x + z)(w' + y)(w' + x' + y')(w + x + y' + z'): a. Express A as a Sum of Minterms b. Express A as a Product of Maxterms c. Express A' as a Sum of Minterms d. Express A' as a Product of Maxterms
- Find the maximum value of the following function F(x)=2x3 , using the genetic algorithm, performing two iterations.'roof: given that f(0) exists, we must show that limx-o f(x)-f(0), or equivalently nat lim f(0+h)+f(0)(if h#0, then.,. ......(Continue h.w)M O \\:\) QUIZ ONE111.DOCX → QUIZ ONE Answer with true or false and correct the false ? a - The signal X(t) is said an even signal if it satisfied the condition X(t) = -X(t) for all t. b- Random signal is the signal that changes randomly with time therefore can be represented mathematically. C--Power signal has infinite power, but its energy is finite. d- Energy signal has infinite energy , while power is zero. e- If f(t+ T/2) = f(t) only odd harmonics are present ,while f( t+T/2 ) = - f(t) only even harmonic are present . %3D II >
- Build a Turing Machine T.M. with three tracks that receives two binary numbers and indicates which of the two is higher. We will consider that the data are stored in the first two tracks and aligned to the right, it means, the least significant bits of both are located in the same column. In the third track it will be written a B, a L or an E, indicating respectively that the first number is larger, smaller or equal to the second.4. The Turing machine M below recognizes the language L = {02" | n ≥ 0}. 0/0, L x/T, L 1/2, R A/A.R A/A, R start- 92 he 24 A/A.R 1/2, R In each of the parts below, give the sequence of configurations that M enters when started on the indicated input string. (a) 00 (b) 000000 Solution: 90 q1 A/A, R: 0/A, R A/A.R ha 0/x, R 0/2, R 95 A/A, L 93x/x, R 0/0, RFor a Turing machine M, (M) refers to the binary representation of M. For a Turing machine M, L(M) contains the set of all strings accepted by M. For a Turing machine M and an input x € {0,1}*, Steps(M, x) refers to the number of steps taken by M to execute on x before it halts. Here, one step of execution of M on x = one movement (left or right) of the tape head. For a Turing machine M and an input x = {0,1}*, we define the following: ReachCells(M,x) = {i : M reaches ith tape cell when M is executed on x} Informally, it contains all locations on the tape that are visited when M is ecuted on x. The leftmost location on the tape is the first tape cell, the location next to it is the second tape cell, and so on. A string w₁ is an anagram of w2 if w₁ can be obtained by rearranging the alphabets of w2. Formally, if w₁ is an n length string, wê is called an anagram of w₁ if there exists a permutation à on n elements such that π(w₁) = W2.