In (y) – In (500 – y) = 500kt + C is the number of infected individuals in an epidemic, t is time, k is a rate constant, and C is another constant. Use log and exponent rules to show that Here 500D y(t) D +e-500kt you encounter an e, re-write it as D to declutter. This is a heavy duty alge- bra problem. If you can do this, you can handle most of the algebraic manipulations that will appear in this class! Hint: the last step is to multiply the numerator and denominator by e When -500kt

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 70E
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I have to turn the equation on the top into the equation on the bottom and I am stuck.
In (y) – In (500 – y) = 500kt + C
%3D
is the number of infected individuals in an epidemic, t is time, k is a rate
constant, and C is another constant. Use log and exponent rules to show that
Here
500D
y(t)
%3D
D+e-500kt
When you encounter an e, re-write it as D to declutter. This is a heavy duty alge-
bra problem. If you can do this, you can handle most of the algebraic manipulations
that will
appear
in this class! Hint: the last step is to multiply the numerator and
denominator by e
-500kt
Transcribed Image Text:In (y) – In (500 – y) = 500kt + C %3D is the number of infected individuals in an epidemic, t is time, k is a rate constant, and C is another constant. Use log and exponent rules to show that Here 500D y(t) %3D D+e-500kt When you encounter an e, re-write it as D to declutter. This is a heavy duty alge- bra problem. If you can do this, you can handle most of the algebraic manipulations that will appear in this class! Hint: the last step is to multiply the numerator and denominator by e -500kt
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