In the fig. shown below we can find the higher critical frequency due to the input is equal to . and the output circuit is equal to . Assume ß = 125, Cbe = 20 pF, and Cbc = 2.4 pF. Vee +10 V Re 2.2 kn C, R 22 kf 10 juF 600 10 uF 22 kf R 4.7 k R 470 O FH(in)= 1.62 MHz and FH(out)= 62.3 MHz FH(in)= 1.82 MHz and FH(out)= 60.3 MHz No option is correct FH(in)= 1.62 MHz and FH(out)= 60.3 MHz O FH(in)= 3.62 MHz and FH(out)= 60.3 MHz Other:

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In the fig. shown below we can find the higher critical frequency due to the input
is equal to . and the output circuit is equal to . Assume B = 125, Cbe =
20 pF, and Cbc = 2.4 pF.
Vc
+10 V
Re
2.2 kn C,
R1
22 kl
10 uF
600
10 jaF
22 kf
R
470 0
V.
4.7 k
FH(in)= 1.62 MHz and FH(out)= 62.3 MHz
FH(in)= 1.82 MHz and FH(out)= 60.3 MHz
No option is correct
FH(in)= 1.62 MHz and FH(out)= 60.3 MHz
FH(in)= 3.62 MHz and FH(out)= 60.3 MHz
Other:
Transcribed Image Text:In the fig. shown below we can find the higher critical frequency due to the input is equal to . and the output circuit is equal to . Assume B = 125, Cbe = 20 pF, and Cbc = 2.4 pF. Vc +10 V Re 2.2 kn C, R1 22 kl 10 uF 600 10 jaF 22 kf R 470 0 V. 4.7 k FH(in)= 1.62 MHz and FH(out)= 62.3 MHz FH(in)= 1.82 MHz and FH(out)= 60.3 MHz No option is correct FH(in)= 1.62 MHz and FH(out)= 60.3 MHz FH(in)= 3.62 MHz and FH(out)= 60.3 MHz Other:
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