If the language L is defined as L = {01,1,100}, select every answer that does NOT belongs to the L*: 110001110011 101011100 100001110001 0111000111111
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- Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)Solution Floating point representation: It is defined as the representation of floating numbers. It includes sign bit, exponent, and mantissa bits. Based on precision it has 2 types. 1. For IEEE 754 single-precision floating-point numbers, what is the exponent of a denormalized floating-point number in decimal? Solution: In IEEE 754 single-precision, exponent bits are 8. Therefore exponent = 2 ^(n-1) -1 = 2^(8-1) -1 = 127 OPTION D 2. For IEEE 754 single-precision floating-point numbers, how many bits for mantissa? Solution: In IEEE 754 single-precision, there are 23 bits for mantissa. sign = 1 bit exponent = 8 bits mantissa = 23 bits 3. For IEEE 754 single-precision floating-point numbers, which of the following is an example of NAN? Solution: In IEEE 754 single-precision, NAN is a special value where all exponents bits are 1's and the mantissa is non zero. a. 1 111 1 111 0000 0000 1101 0000 0000 0000 Exponent is not all 1's. Not a NAN b. 0 111 1 111 1000 0000…A spell checker in a word processing program makes suggestions when it finds a word not in the dictionary. To determine what words to suggest, it tries to find similar words. One measure of word similarity is the Levenshtein distance, which measures the number of substitutions, additions, or deletions that are required to change one word into another. For example, the words spit and spot are a distance of 1 apart; changing spit to spot requires one substitution (i for o). Likewise, spit is distance 1 from pit since the change requires one deletion (the s). The word spite is also distance 1 from spit since it requires one addition (the e). The word soot is distance 2 from spit since two substitutions would be required. a. Create a graph using words as vertices, and edges connecting words with a Levenshtein distance of 1. Use the misspelled word “moke” as the center, and try to find at least 10 connected dictionary words. How might a spell checker use this graph? b. Improve the method…
- int n = 1; int k - 2; int r = n; if (k < n) { r - k2. Write down the object for the operation: 3H*2-2H. Use the opcode provided in Table-I. TABLE I: OPCODE FOR QUESTION- 2 Mnemonics Opcode LDA 0011 ADD 0000 SUB 0010 OUT 1100 HLT 1111Python Language Q2: Ginormous Campus The campus is pretty big. There are n buildings scattered around it, numbered from 0 to n-1. These buildings are so far away from each other that the only way to get from one to another is to take a campus bus. There are m campus bus routes. The i-th one (0 <= i < m) takes you from building u_i to building v_i (but not the other way around). These buses run very frequently. Professor Zingaro is deciding where to hold his CS lectures. He believes a building x is accessible from a building y if you can get from y to x taking at most two buses. For his students’ convenience, he wants to hold his lectures in the most accessible building. Help him out by telling him how many buildings the most accessible building is accessible from. In addition, list all buildings that are the most accessible. Input The first line of the input contains two space-separated integers n and m, denoting the number of buildings and bus routes, respectively. m lines…
- Def der.function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))Debug C language int func(int) main() { int num = 7, c; int f= func(num); printf("\n\n%d of %d\n\n", num, f); } int func(aj); { if(aj=1 aj=0) return 1; else return (aj*fun(aj-1); }