If "shifting by 4" is used in the Caesar cipher, the ciphertext of "FOUR" is O JSYV FRUH JMZI none of them When encrypting and/or decrypting plaintexts/ciphertexts with RC4 cipher, its output is XORed to a data stream. True False
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- Experimenting with AES-128 symmetric key cipher.using python PART 2: you will try to use "brute force" to decrypt an encrypted message, where you only have the first 96-bits of the 128-bit secret key (last 4 bytes of the secret key are missing!) The program should be called "findk", and should deal with two files that contain the encrypted text as a stream of bytes and the first 96-bits of the key, respectively. The program should print out on standard output the missing 4 bytes of the key in hexadecimal, the decrypted message and the time it took to find the correct key.o To test this part, here is the encrypted file (ciphertext2.dat), and the first 96-bits of the key (partial-key.dat) Hint: the original message starts with the word "Salam". Answer you provided .from Crypto.Cipher import AESdef revpad(s):"""This function is to remove padding.parameters:s:strstring to be reverse padded"""k = ord(s[-1])temp = 0 # temporary variable to check paddingfor i in range(1, k): # for loop to…Experimenting with AES-”S symmetric key cipher. Note: You may use any programming language that provided libraries for AES. Descrion: This assignment consists of two parts:PART 1: write a program that uses AES-12/1 to decrypt a message. The program should be named "decrypt", and should deal with three files that contain the encrypted text as a stream of bytes, the 128-bit key for decryption stored as a stream of bytes, and file outcome of the decryption, respectively. o To test this program, here's an example of an encrypted message a. its 128-bit secret key PART 2: you will try to use "brute force" to decrypt an encrypted message, where you only have Sirrst 96-bits of the 12S-bit secret key (last 9 bytes of the secret key are he program should be called "findk", and should deal with two files that contain the encrypted text as a stream of bytes and the first 96-bits of the key, respetively. The program should decryptedn standard the the missing h6177 of the key in hexadecimal,…Given a plaintext in HEX P1=AE1C, the encrypted cipher text is C1-87D2 with key K through stream cipher. Another Cipher text C2=6FF1 is encrypted by the same key K from P2 through stream cipher. Please decrypt the plaintext P2. You should transfer HEX to Binary number then calculate.(Use the property of XOR, don't calculate the key K
- If header files are added please provide them The Caesar cipher is one of the earliest known and simplest ciphers. It is a type of substitution cipher in which each letter in the plaintext is 'shifted' a certain number of places down the alphabet. A B C D E F G H I J K L M N O P Q R S T U V W X Y Z U V W X Y Z A B C D E F G H I J K L M N O P Q R S T H E L L O W O R L D Normal Text B Y F F I Q I R M X Encrypted Text You are tasked to create an encryption program which takes a key word. The keyword will fill the first part of the shifted array. The remaining letters will fill the end of the array. It should look like this: Key=”TOY A B C D E F G H I J K L M N O P Q R S T U V W X Y Z T O Y A B C D E F G H I J K L M N P Q R S U V W X Z You should have an interactive menu with the following options: 1 Enter Key word //takes new key word and…Encrypt this Rail Fence/Caesar Cipher. Imagine that the plaintext has already went through 1 round of encryption. MKBOCI IZX DKDY YQCZBSSK MZIR Hint: This a split key - one part of the key is used for the Caesar and the other part of the key is used for the Rail Fence. The full key (Caesar and Rail Fence], in hexidecimal, is: OXAB. Encrypted message: The Caesar key, in decimal, is: The Rail Fence key, in decimal, is : Is the Caesar key a good random number? . Why? Why not?Q16: if the following message "paperx" is encrypted by using Hill cipher and converted into cipher text "EJGPNH" what is the key matrix if you knowthat the key is (2*2) ?
- Answer questions 1_We can implement block cipher in stream mode by using XOR operation Choose(true or false) 2_For Paillier cryptosystem, if you know the value of the public key (n = 391 and g = 4886), what is the value of the corresponding private key (lamda, mu)? * Jo 9:22 /Find the ciphertext using DES if the shared key is "SECURITY" and the output of round 15 is "IT? 7b/".Find the ciphertext using DES if the shared key is "SECURITY" and round 15's output is "IT? 7b/"?
- 1. Encrypt the message “Take your bag with clothes” using the Hill cipher with the key !3 23 5 <-it is matrixShow your calculations and the result. 2.This problem explores the use of a one-time pad version of the Vigenere cipher. In thisscheme, the key is a stream of random numbers between 0 and 26. For example, if the key is 189 3…, then the first letter of plaintext is encrypted with a shift of 18 letters, the second with ashift of 9 letters, the third with a shift of 3 letters, and so on.Encrypt the plaintext “cryptography” with the key stream10 22 5 4 1 0 2 9 18 16 16 0 3.Does the set of residue classes (mod3) form a group with respect to modular addition?4. Determine -11 mod 95. Determine gcd(65042, 40902)6.Using the extended Euclidean algorithm, find the multiplicative inverse of 1279 mod 9721 Please write the correct answer. Thank you!Assume that a Vigen'ere cipher is used to encrypt a lengthy string of text and that the same string appears in the ciphertext beginning at many locations. For example, explain how the length of the key may be determined by using this informationThe following figure is the Cipher Block Chaining (CBC) mode to encrypt large messages. Which of the followings statement is *correct* regarding this mode? IV m₁ m₂ m3 C3 m4 C4 m5 C5 If a message contains two identical 64-bit blocks, the corresponding ciphertext blocks are also identical. Switching the order of two cipher blocks will not cause any detectable error in the plaintext. Duplicating a cipher block will not cause any detectable error in the plaintext. Deleting a cipher block will cause some detectable error in the plaintext. m6 E encrypt with secret key C6