How much service live load, in kN/m, can be supported?
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- How much service live load, in kN/m, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 45 kN and a service live load of 90 kN. Do not consider moment amplification. Use NSCP 2015. a. b. LRFD. ASD. wt A kN/m mm² W460x144 1.41 18400 472 13.6 283 SECTION tw bf tf Ix Sx mm mm mm mm³ 22.2 726 3080 mm mm mm 199 6.2m W460x144 Sy Ty Zx ly mm mm³ mm 83.6 591 Zy J Cw mmº mm³ mm³ 67.4 3450 906 2440 4230 mmªQ4\ Which of the following is a zero-force member? 3 8KN 4 G 4 エ 子c D. 4 B AC BD IF ID1. For the Pratt bridge truss and the loading shown below, determine the average normal stress in member BE, knowing that the cross-sectional area of that member is 60 in². NN K 12-12--12--12--| 50 lips 50 kips 50. ips Figure 1 G xfone
- Grath fas A cantlever AB o erath lm carries a from klev. uniformly distributed load, wNm fe fired end A to the free end B. Te the cantilever Consista a horizontal thicknees lomm and with 120mm as shown in fhe below, plars plate4 figure calculate the total permiseiblé diafribte load,wif the meximum bending Stress is not exceeding 10OMH/mt. Ignore the grore te weight a the tlefe Im 120mmA flanged cross section is Used to suppaut the lcads shown on the beam on the ext page. The dimen glons oF the ghape are given. Congider the entire om length g Hhe beam and defermine. a:) he maximum tengion bending stres at along he beam and, any location B) te maximum compreggion ben ding stress at any Jocatien along the beam. 20am l00 mm 4.5 YN JOmm Is kN Im 310 mm 270mal AI 1. 5m 1.2m 1o mm 20nmEYA 98 B/s docs.google.com/forms 100 Papertine J MA Papertine Papertine 45 - ls- das #2: For the Simply supa ted beam having the Sechin Shown and londed partially, Find: 1. Draw the bending moment diagram ? 2. Find the value of the maximum bendig moment Mmak 3. Find the value f the maximum bending stress Vmax ال لعة البطم رات المطع الو ضع المكل والحملة ۱. أسم الر البان لعن اوكماو : Mmax sls! e de i ană fic أوجه تعة أ على إ دإما کے ļ Umax KN/m - 20 Cm 4 1 m. 2 m. 1 m. Neutral 40 cm Axis Beam (AB) Beam Cross- Section ت إضافة ملف
- Where is/are the location(s) of the maximum transverese shear stress? A simple I-beam is loaded as shown. 20 mm P KN PKN PKN Į Į -C B с D L/4 m L/4 m Midspan at point C Roller at E at the NA Section B at the top fiber Pin A at point C Midspan at point D Roller E at point D L/4 m L/4 m OE 20 mm 20 mm- 250 mm 150 mm 150 mm ADETERMINE THE THE IS MAXIMUM SAFE SERVICE LIVE LOAD THAT THE BEAM CAN CAN CARRY IF SERVICE DEAD L O A D THE BEAM WEIGHT OF THE BEAM SECTION fy = 415 MPa. TOP BARS BOTTOM BARS ARE CENTER DISTANCE 12 KM/M INCLUDING AND BASED ON THE CAPACITY SHOWN. fc : 40 MPa AND ARE 6-32 mm. AND ARE - 3 - 28 mm. CENTER TO 3 BETWEEN THE USE 2015 NSCP Is 108 mm 00 0 0 300 G ט1 108 352 70. A (1 7.2m B TOP BAR LAYERS ↓ 6.7M C OMDe term ine the kin d and am ount of stress in e ach mem ber of the truss shown by the method of jo in ts in figure P 5-2 (page 76).- 1000lb 1000lb 1000lb 1000Ib 1000 Ib U. h = 20 ft 500lb 500 Ib L. L. RAV 6 pane ls at 10' - 6 ft RBy Note: 1. F o llo w strictly the lecture notes g iv en. Draw the FBD of e ach jo in t 2. Sum m a rize and tabu la te your answers. 3. Compu te the bar forces up to member U,L3 on ly because the truss lo a d in g is sym metric aland the bar forces of right sid e members are id en tic al w ith th e left s ide members. But you in c lu de th e rig ht sid e mem bers in have to the tabu la tion. 4. Show the com puta tio n ho w the leng th s were obta in ed. 5. Look for your own data in the table provided. 6. Copy the problem , data of problem and fig ure of the proble m TABULAT ION FOR SUMMAR Y OF COMPUTATION OF BAR FORCES METHOD OF JOINTS (PROBLEM P5-2 PAGE 76) Mem ber Identification Length Bar Forc e Туре of ft Ib force LOL1 10 3750 Tensio n L1L 2 10 Tension…
- 8. H / The beam shown below has across seclion of channel Shape with width 360mm.and haghs h= loomm, the web thickness ist= 14mm.Deler- Mine ihe Max imum tensile aud Compressive stressin the beam due to unifom Load? 360Mm 3.6KN/M 14m tiom Please Sir 5T CASIC f-991ES PL DATURAL u CALC (-)Link AC is made of a steel with a 450-MPa ultimate normal stress and has a 6 x 12-mm uniform rectangular cross section. It is connected to a support at A and to member BCD at C by 8-mm diameter pins, while member BCD is connected to its support at B by a 10-mm diameter pin. All the pins are made of steel with a 170-MPa ultimate shear stress and are in single shear. Kwing that a factoaety f32is desired. 12 mm 200 mm It is required to determine the largest load P that may be applied at D. Note that link AC is not reinforced around the pin holes. 150 mm 104-47. The support consists of a solid red brass C83400 post surrounded by a 304 stainless steel tube. Before the load is applied the gap between these two parts is 1 mm. Determine the greatest axial load that can be applied to the rigid cap A without causing yielding of any one of the materials. A 0.25 m = 1 mm 60 mm 80 mm Prob. 4-47 -10 mm