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Here is the partial ANOVA result. Source of Variation SS df MS F Drying Technique Batch Error Total 89.2 363.6 46.8 499.6 The value of the F test statistic for testing whether there is a significant difference among the drying techniques so far as their effect on compressive strength is concerned is Round off your answer to 2 decimal places. Hence, there (choose from is or is no) sufficient evidence to reject the null hypothesis at the 0.05 level of significance.

Here is the partial ANOVA result. Source of Variation SS df MS F Drying Technique Batch Error Total 89.2 363.6 46.8 499.6 The value of the F test statistic for testing whether there is a significant difference among the drying techniques so far as their effect on compressive strength is concerned is Round off your answer to 2 decimal places. Hence, there (choose from is or is no) sufficient evidence to reject the null hypothesis at the 0.05 level of significance.

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.2: The Least Square Line
Problem 8E
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Here is the partial ANOVA result. Source of Variation SS df MS F Drying Technique Batch Error Total 89.2 363.6 46.8 499.6 The value of the F test statistic for testing whether there is a significant difference among the drying techniques so far as their effect on compressive strength is concerned is Round off your answer to 2 decimal places. Hence, there (choose from is or is no) sufficient evidence to reject the null hypothesis at the 0.05 level of significance.
Transcribed Image Text:Here is the partial ANOVA result. Source of Variation SS df MS F Drying Technique Batch Error Total 89.2 363.6 46.8 499.6 The value of the F test statistic for testing whether there is a significant difference among the drying techniques so far as their effect on compressive strength is concerned is Round off your answer to 2 decimal places. Hence, there (choose from is or is no) sufficient evidence to reject the null hypothesis at the 0.05 level of significance.
Suppose you are manufacturing concrete cylinders for, say, bridge supports. There are three ways of drying green concrete (say A, B, and C), and you want to find the one that gives you the best compressive strength. The concrete is mixed in batches that are large enough to produce exactly three cylinders, and your production engineer believes that there is substantial variation in the quality of the concrete from batch to batch. You have data from a completely randomized block design with 5 batches on each of the 3 drying process techniques. Your measurements are the compressive strength of the cylinder in a destructive test. Here is the partial ANOVA result.
Transcribed Image Text:Suppose you are manufacturing concrete cylinders for, say, bridge supports. There are three ways of drying green concrete (say A, B, and C), and you want to find the one that gives you the best compressive strength. The concrete is mixed in batches that are large enough to produce exactly three cylinders, and your production engineer believes that there is substantial variation in the quality of the concrete from batch to batch. You have data from a completely randomized block design with 5 batches on each of the 3 drying process techniques. Your measurements are the compressive strength of the cylinder in a destructive test. Here is the partial ANOVA result.
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