Given: diameter of pipe in point 1 = 3.9in diameter of pipe in point 2 = 2.5in specific gravity of the liquid = 0.79 h(ft) = 0.60ft pressure at point 1 = 14.6 psia pressure at point 2 = 49 psia pump and motor efficiency = 66% diameter of pipe in point 4 = 4.5in diameter of pipe in point 5 = 2.3 in Z3 = 35ft With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp)

Given: diameter of pipe in point 1 = 3.9in diameter of pipe in point 2 = 2.5in specific gravity of the liquid = 0.79 h(ft) = 0.60ft pressure at point 1 = 14.6 psia pressure at point 2 = 49 psia pump and motor efficiency = 66% diameter of pipe in point 4 = 4.5in diameter of pipe in point 5 = 2.3 in Z3 = 35ft With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp)

Name: Given:diameter of pipe in point 1 = 3.9indiameter of pipe in point 2 =
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Description: Given:diameter of pipe in point 1 = 3.9indiameter of pipe in point 2 = 2.5inspecific gravity of the liquid = 0.79h(ft) = 0.60ftpressure at point 1 = 14.6 psiapressure at point 2 = 49 psiapump and motor efficiency = 66%diameter of pipe in point 4 = 4.

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter3: Transient Heat Conduction

Section: Chapter Questions

Problem 3.37P

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