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Given: 8 = 880 Kg/m³ m = 10 kg/s = 88.9mm 3.5x25.4= 88.9x10³m - 1 &in = 1.625in = 1.625x25.4 = 41.275mm= 41.275x15³m for d₁ = 3 — in = 3.5in = da From figure 2₁ = 55 ft 2₂=0 gage pressure 55 3.281 ! P₂ = Patm = 0 16.763m -

Given: 8 = 880 Kg/m³ m = 10 kg/s = 88.9mm 3.5x25.4= 88.9x10³m - 1 &in = 1.625in = 1.625x25.4 = 41.275mm= 41.275x15³m for d₁ = 3 — in = 3.5in = da From figure 2₁ = 55 ft 2₂=0 gage pressure 55 3.281 ! P₂ = Patm = 0 16.763m -

Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
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→ The mass flow rate : Y₁ = = m ९ Idi² Sad ² m = SA⋅V 10kg/s 880 K xx (88.9x10³)² m² m3 V 10kgls 880 kg x X(41.275x10³) m² X m³ 4 Apply Bernoulli equation (1 and 2): = 880 x = 0 1/2 + 1² +²₁= ² + 1² + P₁ un гд 3g гд 3g P₁ = 3 [ 12 (V₂² - V₁²) - 9x₁] P₁ = = 114,449.778 N/m² | P₁ = = 114,449.778 Pa i SA = 1.83073m/s = 8.49285 mls x [2 (8.49285² 1.830+3²) - (9.81 X 16.763) +½Ã°
Transcribed Image Text:→ The mass flow rate : Y₁ = = m ९ Idi² Sad ² m = SA⋅V 10kg/s 880 K xx (88.9x10³)² m² m3 V 10kgls 880 kg x X(41.275x10³) m² X m³ 4 Apply Bernoulli equation (1 and 2): = 880 x = 0 1/2 + 1² +²₁= ² + 1² + P₁ un гд 3g гд 3g P₁ = 3 [ 12 (V₂² - V₁²) - 9x₁] P₁ = = 114,449.778 N/m² | P₁ = = 114,449.778 Pa i SA = 1.83073m/s = 8.49285 mls x [2 (8.49285² 1.830+3²) - (9.81 X 16.763) +½Ã°
Giveni = 880 Kg/m³ m = 10 kg/s From figure : for d₁ = 3 — — in = 3.5in = 3.5x25.4 = 88.9mm d₂ = 1 {√ in = 1.625in = 1.625x25.4 = 41.275mm= 41.275x16³m 2₁=55ft = 55 = 16.763m 3.281 2₂=0 gage pressure =0 88.9x10³m : P₂ = Patu:
Transcribed Image Text:Giveni = 880 Kg/m³ m = 10 kg/s From figure : for d₁ = 3 — — in = 3.5in = 3.5x25.4 = 88.9mm d₂ = 1 {√ in = 1.625in = 1.625x25.4 = 41.275mm= 41.275x16³m 2₁=55ft = 55 = 16.763m 3.281 2₂=0 gage pressure =0 88.9x10³m : P₂ = Patu:
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