From Example 2.1 the maximum diversified kW demands were computed. Using the 0.9 lagging power factor, the maximum diversified kW and kVA demands for the line segments and transformers are Segment N1-N2: P12 = 92.8 kW S12 = 92.8 + j45.0 kVA S3 = 72.6 + j35.2 kVA Su = 48.9 + j23.7 kVA S = 30.3 + j14.7 kVA Segment N2-N3: P23 = 72.6 kW %3D Segment N3-N4: P4 = 48.9 kW Transformer T1: P = 30.3 kW %3D Transformer T2: Pr2 = 35.5 kW S2 = 35.5 + j17.2 kVA %3D Transformer T3: Pr3 = 48.9 kW ST3 = 48.9 + j23.7 kVA %3!

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.29P: Consider three ideal single-phase transformers (with a voltage gain of ) put together as ...
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Q)The question is that how kW is converted to kVA in complex form and how kV square is 2.4 for T1,T2,T3 can you plz explain it by seeing the solution

Example 2.3
For the system of Example 2.1, assume the voltage at N1 is 2400 volts and
compute the secondary voltages on the three transformers using the diversity
factors. The system of Example 2.1, including segment distances, is shown
in Figure 2.12.
Assume that the power factor of the loads is 0.9 lagging.
The impedance of the lines are: z = 0.3 + j0.6 2/mile
The ratings of the transformers are
T1:
25 kVA, 2400-240 volts,
Z = 1.8/40%
T2:
37.5 kVA, 2400-240 volts, Z = 1.9/45%
T3:
50 kVA, 2400-240 volts,
Z = 2.0/50%
From Example 2.1 the maximum diversified kW demands were computed.
Using the 0.9 lagging power factor, the maximum diversified kW and kVA
demands for the line segments and transformers are
Segment N1-N2:
P12 = 92.8 kW
S12 = 92.8 + j45.0 kVA
Segment N2-N3:
P23 = 72.6 kW
S23 = 72.6 + j35.2 kVA
Segment N3-N4:
P4 = 48.9 kW
S34 = 48.9 + j23.7 kVA
Transformer T1:
P = 30.3 kW
STI = 30.3 + j14.7 kVA
Transformer T2:
Pr2 = 35.5 kW
S12 = 35.5 + j17.2 kVA
Transformer T3:
Pr3 = 48.9 kW
S13 = 48.9 + j23.7 kVA
The Nature of Loads
29
Convert transformer impedances to ohms referred to the high-voltage side
kV - 1000
kVA
2.4 - 1000
T1: Zbase =
= 230.4 2
25
ZTI = (0.018 /40) · 230.4 = 3.18 + j2.67 2
kV² - 1000
kVA
4² . 1000
37.5
T2: Zbase =
= 153.6 2
ZT2 = (0.019/45) · 153.6 = 2.06 + j2.06 2
kV? . 1000
kVA
2.4 - 1000
T3: Zbase =
= 115.2 Q
%3D
50
Z73 = (0.02/50) 115.2 = 1.48 + j1.77 2
Transcribed Image Text:Example 2.3 For the system of Example 2.1, assume the voltage at N1 is 2400 volts and compute the secondary voltages on the three transformers using the diversity factors. The system of Example 2.1, including segment distances, is shown in Figure 2.12. Assume that the power factor of the loads is 0.9 lagging. The impedance of the lines are: z = 0.3 + j0.6 2/mile The ratings of the transformers are T1: 25 kVA, 2400-240 volts, Z = 1.8/40% T2: 37.5 kVA, 2400-240 volts, Z = 1.9/45% T3: 50 kVA, 2400-240 volts, Z = 2.0/50% From Example 2.1 the maximum diversified kW demands were computed. Using the 0.9 lagging power factor, the maximum diversified kW and kVA demands for the line segments and transformers are Segment N1-N2: P12 = 92.8 kW S12 = 92.8 + j45.0 kVA Segment N2-N3: P23 = 72.6 kW S23 = 72.6 + j35.2 kVA Segment N3-N4: P4 = 48.9 kW S34 = 48.9 + j23.7 kVA Transformer T1: P = 30.3 kW STI = 30.3 + j14.7 kVA Transformer T2: Pr2 = 35.5 kW S12 = 35.5 + j17.2 kVA Transformer T3: Pr3 = 48.9 kW S13 = 48.9 + j23.7 kVA The Nature of Loads 29 Convert transformer impedances to ohms referred to the high-voltage side kV - 1000 kVA 2.4 - 1000 T1: Zbase = = 230.4 2 25 ZTI = (0.018 /40) · 230.4 = 3.18 + j2.67 2 kV² - 1000 kVA 4² . 1000 37.5 T2: Zbase = = 153.6 2 ZT2 = (0.019/45) · 153.6 = 2.06 + j2.06 2 kV? . 1000 kVA 2.4 - 1000 T3: Zbase = = 115.2 Q %3D 50 Z73 = (0.02/50) 115.2 = 1.48 + j1.77 2
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