For the circuit below, find V, and the power absorbed by the 402 resistor. (Concept: Mesh/ Nodal Analysis) 24 V 2492 www + V₂ 3Ω OV₂ = 12 V, P = 5.06 W OV₂ = 12 V, P = 41.06 W OV₂ = -12 V, P = 41.06 W OV₂ = 36 V, P = 5.06 W OV₂ = 36 V, P = 30.93 W OV₂=4.5 V, P = 30.93 W OV₂ = -36 V, P = 5.06 W 4 A 492 12Ω 12 V
For the circuit below, find V, and the power absorbed by the 402 resistor. (Concept: Mesh/ Nodal Analysis) 24 V 2492 www + V₂ 3Ω OV₂ = 12 V, P = 5.06 W OV₂ = 12 V, P = 41.06 W OV₂ = -12 V, P = 41.06 W OV₂ = 36 V, P = 5.06 W OV₂ = 36 V, P = 30.93 W OV₂=4.5 V, P = 30.93 W OV₂ = -36 V, P = 5.06 W 4 A 492 12Ω 12 V
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter23: Resistive-inductive-capacitive Series Circuits
Section: Chapter Questions
Problem 9RQ: What is the power factor of the circuit in Question 6?
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