For each case below draw a ray diagram. Draw the image as an arrow and give a description of the image. 5. Description of Image: Location: 0: Upright or Inverted S: Magnified or Reduced T: Real or Virtual 6. F Description of Image: Location: 0: Upright or Inverted S: Magnified or Reduced T: Real or Virtual

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A: Heren1=1.70n2=1.50n3=1.30

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A: Given information: The index of refraction of the prism (n) = 1.52 The refractive index of air…

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A: Required : Ray diagram of the image

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Q: 7 cm 35 cm

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A: The Snell's law of refraction is given as, n1sinθ1=n2sinθ2 ......................................…

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Q: For each case below draw a ray diagram. Draw the image as an arrow and give a description of the…

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A: This problem can be solved by using snell's law in refraction.

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Q: C.) D.) 2F 2F F 2F 2F

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Q: 2F F' 2F'

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Q: A 2.0-cm-tall object is 50 cm in front of a converging lens that has a 25 cm focal length.

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Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.