Find an orthogonal change of variables that eliminates the cross product terms in the quadratic form Q, and express Q in terms of the new variables. 7x + 6x3 + 5x – 4x1.x2 + 4x2x3 2 A substitution x = Py that eliminates cross-product terms is x =-yı + y2 - „¥3, X2 = –; 1 2 2 1 2 32 + 3Y3, 2 2 1 X3 = -y1 + Y2 – ¬V3. The new quadratic form is 3y – 6y + 9y. 3 O A substitution x = Py that eliminates cross-product terms is x1 = - yı+ 2y2 - 2y3, x2 = - 2y1 + Y2 + 2y3, X3 = 2y1 + 2y2 + y3. The new quadratic form is 3y + 6y + 9y. 1 A substitution x = Py that eliminates cross-product terms is x = - 2 2 V2 - 2 1 yi +y2 + X2 = - 2 2 1 X3 = 7Y1 + y2+ V3. The new quadratic form is 3y + 6y} + 9y?. 2 A substitution x = Py that eliminates cross-product terms is x = - 1 VI - 2 2 2 Yi +z2 +V3. The new quadratic form is 6y + 5y + 3y. 1 X3 = 7V1 O A substitution x = Py that eliminates cross-product terms is x1 = - y1 - 2y2 - 2y3, X2 = - 2y1 - Y2+ 2y3, X3 = 2y1 + 2y2 +y3. The new quadratic form is 9y + 3y + 6y?.

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Find an orthogonal change of variables that eliminates the cross product terms in the quadratic form Q, and express Q in terms of
the new variables.
7x구 +6x2 + 5x금-4r x2 + 4x2.13
2
A substitution x = Py that eliminates cross-product terms is xį = -y1 +Y2 - V3, x2 = -z1 + zy2 +zV3,
2
1
X3 = -V1 + V2 – V3. The new quadratic form is 3y – 6y + 9y?.
O A substitution x = Py that eliminates cross-product terms is x1 = - y1+ 2y2 - 2y3, X2 = - 2y1+ y2+ 2y3, X3 = 2y1+2y2 + y3-
The new quadratic form is 3y + 6y + 9y.
2
1
+
2
2
A substitution x = Py that eliminates cross-product terms is x = -
2
X2 =
1
+
+
1
V2 + zV3. The new quadratic form is 3y + 6y + 9y.
X3 =
1
2
2
2
A substitution x = Py that eliminates cross-product terms is x = -I -2 -y3, x2 = -1 - 32 + 33,
2
1
X3 = 7Y1 + zV2 + V3. The new quadratic form is 6y+ 5y + 3y.
O A substitution x = Py that eliminates cross-product terms is x1 = - y1- 2y2 - 2y3, X2 = - 2y1 – Y2+ 2y3, X3 = 2y1+2y2 + y3-
The new quadratic form is 9y + 3y + 6y.
Transcribed Image Text:Find an orthogonal change of variables that eliminates the cross product terms in the quadratic form Q, and express Q in terms of the new variables. 7x구 +6x2 + 5x금-4r x2 + 4x2.13 2 A substitution x = Py that eliminates cross-product terms is xį = -y1 +Y2 - V3, x2 = -z1 + zy2 +zV3, 2 1 X3 = -V1 + V2 – V3. The new quadratic form is 3y – 6y + 9y?. O A substitution x = Py that eliminates cross-product terms is x1 = - y1+ 2y2 - 2y3, X2 = - 2y1+ y2+ 2y3, X3 = 2y1+2y2 + y3- The new quadratic form is 3y + 6y + 9y. 2 1 + 2 2 A substitution x = Py that eliminates cross-product terms is x = - 2 X2 = 1 + + 1 V2 + zV3. The new quadratic form is 3y + 6y + 9y. X3 = 1 2 2 2 A substitution x = Py that eliminates cross-product terms is x = -I -2 -y3, x2 = -1 - 32 + 33, 2 1 X3 = 7Y1 + zV2 + V3. The new quadratic form is 6y+ 5y + 3y. O A substitution x = Py that eliminates cross-product terms is x1 = - y1- 2y2 - 2y3, X2 = - 2y1 – Y2+ 2y3, X3 = 2y1+2y2 + y3- The new quadratic form is 9y + 3y + 6y.
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