Please solve again, there are 2 answers wrongf'(x) & f(-1/2) https://www.webassign.net/web/Student/Assignment-Respons E业y20ЕXAMPLE 8Find the absolute maximum and minimum values of the function below.rX) = x - 3x2 +3152.SOLUTIONSince f is continuous onwe can use the Closed Interval Method:102]F(x) =x3 - 3x2 + 3F(x) 3x-6x%3D-11.49.Since f(x) exists for all x, the only critical numbers of f occur when f'(x) =14thatis, x = 0 or x = |2. Notice that each of these critical numbers lies inThe2values of fat these critical numbers are(0) = 3)and(2) = |-1The values of f at the endpoints of the interval areand(4) = 192.Comparing these four numbers, we see that the absolute maximum value is (4) = 19and the absolute minimum value is f(2) = |-1Note that in this example the absolute maximum occurs at an endpoint, whereas the absoluteminimum occurs at a critical number. The graph of fis sketched in the figure.Need Help?Read ItSubmit Answer人étv A30MacBook Air3.

Given function is : fx=x3-3x2+3 Differentiating with respect to 'x', we get…

Answered: EXAMPLE 8 Find the absolute maximum and…

Math

Calculus

EXAMPLE 8 Find the absolute maximum and minimum values of the function below. f(x) = x - 3x + 3

Trigonometry (MindTap Course List)

10th Edition

ISBN:9781337278461

Author:Ron Larson

Publisher:Ron Larson

ChapterP: Prerequisites

SectionP.7: A Library Of Parent Functions

Problem 47E

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Question

Please solve again, there are 2 answers wrong

f'(x) & f(-1/2)

https://www.webassign.net/web/Student/Assignment-Respons E
业
y
20
ЕXAMPLE 8
Find the absolute maximum and minimum values of the function below.
rX) = x - 3x2 +3
15
2.
SOLUTION
Since f is continuous on
we can use the Closed Interval Method:
10
2]
F(x) =
x3 - 3x2 + 3
F(x) 3x-6x
%3D
-1
1.
4
9.
Since f(x) exists for all x, the only critical numbers of f occur when f'(x) =14
that
is, x = 0 or x = |2
. Notice that each of these critical numbers lies in
The
2
values of fat these critical numbers are
(0) = 3
)
and
(2) = |-1
The values of f at the endpoints of the interval are
and
(4) = 19
2.
Comparing these four numbers, we see that the absolute maximum value is (4) = 19
and the absolute minimum value is f(2) = |-1
Note that in this example the absolute maximum occurs at an endpoint, whereas the absolute
minimum occurs at a critical number. The graph of fis sketched in the figure.
Need Help?
Read It
Submit Answer
人
étv A
30
MacBook Air
3.

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