consists oI three prislmatic segm s-sectional area A1 = 800 mm and leng Az = 1500 mm² and length L2 = 250 m
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- A lube structure is acted on by loads at B and D, as shown in the figure. The tubes are joined using two flange plates at C that are boiled together using six 0.5-in. diameter bolts. (a) Derive formulas for the reactions RAand REat the ends of the bar. (b) Determine the axial displacements S£. Sc, and SDat points B, C. and D. respectively. (c) Draw an axial-displacement diagram (ADD) in which the abscissa is the distance x From support A to any point on the bar and the ordinate is the horizontal displacement Sat that point. (d) Find the maximum value of the load variable P if allowable normal stress in the bolts is 14 ksi.Wires B and C are attached to a support at the left-hand end and to a pin-supported rigid bar at the right-hand end (see figure). Each wire has cross-sectional area A =0.03 in2 and modulus of elasticity E = 30 X 106 psi. When the bar is in a vertical position, the length of each wire is L = 80 in. However, before being attached to the bar, the length of wire B was 79.98 in. and wire C was 79.95 in. Find the tensile forces TBand Tc in the wires under the action of a force P = 700 lb acting at the upper end of the bar.Q2- For the frame shown in Figure (2), determine the reactions at A and C. 2m, 2m 20 AN 150 kNm 6m 100 LN 3m D Figure (2)
- Determine the value of reactions at the supports A & B. see Figure2. Figure 2 15 KN/m 1ORN/m Brn 4m 3mA truss structure is shown in Figure A1-1. The member AB is along the horizontal direction. A horizontal force F=100 N is applied on joint C. Co F=100N 45° D 90⁰ A 45⁰ 45° B 1m Figure A1-1 (a) Determine the reaction forces at joints A and B. (b) Determine the loads carried by all the members (AB, BC, BD, AD and DC). Indicate if they are tensile or compressive. 90° 45⁰ 1m- For the frame of the figure:a) Draw up the free-body diagram of the three elements that compose it, for the BCD element, set theequilibrium equations (summation of forces along the longitudinal axis "t" and the perpendicular "n", as well as thesummation of moments at point C). Note: it is not required to evaluate the reactions or the charges on the elements.b) Make a cut at the midpoint between C and D and “CALCUE” the internal loads numerically.
- Figure 1 below shows the bronze and galvani pipes are fastened to rigid supports at ends A and B and to a rigid plate C at their junction. The bronze pipe is twice as long as the galvani pipe. Two equal and symmetrically placed loads P act on the plate at C 1)Write one equilibrium equation involving reaction forces of the pipes with the help of free body diagram.[Note: Show all the forces acting on the members.] 2)Derive equilibrium equations for internal forces for section AC and BC with the help of respective free body diagrams.[Note: Show all the forces acting on the members.]Problem 3. As shown in the Figure below, please determine the internal force in the middle of AB, with the given data: OA-15 cm, OB-30 cm, OC-60 cm. W=40N, Wo=60N. F=1214N, B-10°, FM=1236 N, and 8=15%. Fj B FM W Wo 4Figure Q1(a) shows a bracket that has a load of 1.6 kN applied at one end as shown in the figure. The bracket is supported by a pin at the end A and by a roller which rests on a rigid surface near pin B as illustrated in the figure. i) Draw the free body diagram for the bracket together with the roller. ii) Calculate the reaction of the support on the roller i) Calculate the magnitude and direction of the reaction at the pin A -120 mm- B. 30° -180 mm 1.6 kN Figure Q1(a)
- 3. For the bar assemblages shown in figure, determine the nodal displacements, the forces in each element, and the reactions. Use the direct stiffness method for these problems. O 30 in. 2 5000 lb 10,000 lb 3 30 in. 30 in. E 30 x 10 psi A = 4.0 inDetermine the supports reactions in the figure shown: 80KN 20KN/m 30kN 60KN-m 2m A B C -3m Am- t 3met 2m' 2m ANS. Ax kN, Ay = kN, By = kN (two decimal places)For the bar assemblages shown in Figure P3-3, determine the nodal displacements, the forces in each element, and the reactions. Use the direct stiffness method for the problem. 16,000 Ib 2 E - 30 x 10 psi A = 2.0 in? 20 in. 50 in. Figure P3-3