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Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis.    Find the equations of motion in terms of x.  Select all that apply.

Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis.    Find the equations of motion in terms of x.  Select all that apply.

Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.14P: Solve the preceding problem for the following data: x=1120106,y=430106,xy=780106,and=45.
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Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. 

 

Find the equations of motion in terms of x.  Select all that apply.
Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. R m1 Find the equations of motion in terms of x. Select all that apply. Selected Answers: O [None Given] Answers: (4m1 + m, + |/ R2) dx (t) +2kx = 2m1g +m2g dt? d²x (t) (4m1 + |/R2) dt? + kx = 2m1g +m2g d?x(t) (m1+ 4m2 + 1/ R?)- dt? + 2kx = - (m1g + 2m2g) d²x (t) + kx = - (2m1g +m2g) dt? (4m1 + m2 + 1/ R²) (4m1 + m2 + 1/ R?) dʻx(t) dt? + 4kx = m1g +2m2g d?x (t) + kx = 2m1g + m2g dt? (4m1 + m2 + 1/ R²)
Transcribed Image Text:Consider a pulley system shown below. Assume there is no slip between the cord and the pulley. I is the mass moment of inertia of the pulley about its own centroidal axis. R m1 Find the equations of motion in terms of x. Select all that apply. Selected Answers: O [None Given] Answers: (4m1 + m, + |/ R2) dx (t) +2kx = 2m1g +m2g dt? d²x (t) (4m1 + |/R2) dt? + kx = 2m1g +m2g d?x(t) (m1+ 4m2 + 1/ R?)- dt? + 2kx = - (m1g + 2m2g) d²x (t) + kx = - (2m1g +m2g) dt? (4m1 + m2 + 1/ R²) (4m1 + m2 + 1/ R?) dʻx(t) dt? + 4kx = m1g +2m2g d?x (t) + kx = 2m1g + m2g dt? (4m1 + m2 + 1/ R²)
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