CI H2 Pd 1000 psi AICI3 (h-i) 1 equivalent CH3S K* () O2N. CI CI 1. SO3 AICI3 (k-I) -CH3 H2SO4 2. excess NH2NH2 КОН CH3CH2. CH2CH3 Na KMNO4 (m-n) excess NH3 CH2CH3
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- 0.00130 molk (CH2)NH* POH = - log (u.8x 10-5) - log (0.8x 10-s) 4.50 + 20.0D = 214.50 x 10-3L log 0.00110 mols (CH)N 24.50 x 10-3LH3O* (aq) + OAC° (aq) Н2о () + НОАc (аq) +» НҙО* (аq) + ОАc" (аq) the Dissociation Constant Ka of HOAC: Ka = [HOAC]/([H30*][OAC¯]) Ka = [H3O*][OAc]/([HOAC][H2O]) Ka = [H3O*][OAc"]/[HOAC] O Ka = [HOAC][H2O]/([H3O*][OAC¯]) %3D||||OH 1.pTs-Cl 2. KCN/DM50 1 1. SOCl₂, pyridine 2. KOH/acetone 1. HCI 2. (CH3)3COK acetone K J
- X app.101edu.co # 3 E UL Week 7: Panopto DII 0 F3 $ R F4 X UL LTU 7-1A Identify the best conditions to complete the SN2 reaction shown below. H % 5 T N3 گیا QL FS A 6 Y Question 18 of 24 40 X F6 & 7 C|Chegg.com U F7 8 A) CH3I, THF B) NaCN, DMSO C) NaN3, ethylamine D) KI, THF X + E) NaN3, DMF PrtScn FB Home ( 9 F9 O ) End 0 & 3 ENG F10 P PgUp - F11 Tp S <10) 1 PgDn D + 6:16 PM 10/18/2022 F12H30* d. [1] CH3OH, H* CH30 HO. MgBr е. [2] (2 equiv) [3] H20 HO [1] SOCI, f. [2] CH3CH,CH,CH,NH2 [3] LIAIH4 [4] H2Ok esc ~ 1. LiAlH4 2. Neutralizing work-up Select to Draw ! F1 F2 < O Q #つ 80 F3 NaCN, HCI Select to Draw $ 000 000 F4 % L F5 Problem 4 c MacBook Air < ( F6 8
- Help 100% 2 Tue 4: Public Health Ch x * HSC 258 - Major Projec X * Mind Tap - Cengage Lea X C The Illustration To The d=55750828934189288909969212&EISBN=9781305657571&id=1061392007&nbld%3D21... * O TO Q Search this co References Use the References to access important values if needed for this question. For the following reaction, 6.43 grams of sulfur dioxide are mixed with excess oxygen gas . The reaction yields 6.30 grams of sulfur trioxide . sulfur dioxide(g) + oxygen(g) sulfur trioxide(g) grams What is the ideal yield of sulfur trioxide? What is the percent yield for this reaction? Submit AnswerRCO3H 1) Mg Br 2) CO₂ b) 3) H c) CO₂H 1) LiAlH4 2) H3O+ d) SOCI2 CO₂H (CH3)2CuLi CI 1) LIAI(OR)H, f) CI 2) H* g) h) J) H CO2H + CH3OH O-CH3 1) CH3MgBr (2 equiv.), 2) H3O+ CN 1) CHзMgBr 2) H₂O* CN 1) LiAlH4 2) H₂O6. Calculate Kc for 2N204(6) + 3021e) - 2N20 (e) K=? using.. Reaction 1 2N2e) + O2le) - 2N,0 (2) K, = 1.2 x 1035 2NO2 (6) K2 = 4.6 x 103 Reaction 2 ½ N21e) + O218) e NO2 (2) K3 = 4.1 x 10° Reaction 3
- 1. LIAIH4 (excess) 2. H3O* NaBHa (еxcess) D CH3OH `NH2 1. LIAIH4 (excess) E `CI 2. H20, H3O* Br NaBHa (еxcess) F CH3OH LIAIH4 'N' G NaOCH3 H CH3OHReaction Conc, Na,d O3| Cune. HCI 4Als. | AIme (3) Rabe I1.3085840 0.10M •30M 0.4563/64 |0.028 F0913 15 M 12267196 | 0,01870913 30M 1.5360817 0.300349 2 65.56796607 5. 11431671 O.10 M 3 0.050 M 4 0.025 M 0:30M 1.54866|1 1.007568 1,358380874 4. Use experimental data and the rate law to calculate a rate constant for each reaction 1, 2, 3, 4. How do the rate constants compare? Should they be the same or different? Discuss in your conclusions. Report the average value of your calculations. Be sure to include units in your rate constant. -1-4 -2:5 Rate= k [ Naz s03] [Hc1][Relerences Use the References to access important values if needed for this question. Complete the following operations by filling in the exponent for the result: = k (-)*- = a (-)(**)-a Veited Submit Answer Retry Entire Group No more group attempts remain