Calculate the strength and direction of the electric field due to a point charge of 2.00 nC at a distance of 15.00 mm from the charge. Write your answer in whole number.
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Calculate the strength and direction of the electric field due to a point charge of 2.00 nC at a distance of 15.00 mm from the charge. Write your answer in whole number. No unit required.
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- A point charge q1 =8.0 nC is at the origin and another point charge q, = 12.0 nc is on the x-axis at x=4.0 m. Find the electric field at (x=0,y=3.0 m). Express all numerical values in three significont figures. Calculate the electric field component due to each point charge. Fill out the table below. Expressal numerical volues in three significont figures. Do not forget to include the sign if the value is negative. E, (N/c) E, (N/c) electric field due to charge 1 E electric field due to charge 2 E2 net electric field From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is |ZE|= N/CA point charge qı =8.0 nCis at the origin and another point charge q2 = 12.0 nC is on the x-axis at X = 4.0 m. Find the electric field at (x=0, y=3.0 m). Express oll numerical values in three significant figures. Calculate the electric field component due to each point charge. Fill out the table below. Express all numericol values in three significant figures. Do not forget to include the sign if the value is negotive. E, (N/c) E, (N/c) electric field due to charge 1 Ei electric field due to charge 2 E, net electric field From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is N/CThe electric field strength at a distance of 2.00 cm from a 2.1 x 10-5 C point charge, expressed in scientific notation, is a.bc x 10dN/C. What are The values of a,b,c and d?
- A 27 nC charge generates an electric field within an isolated chamber. At a point a distance d meters away from the charge, the electric field is measured to be 4 N/C. Determine d in meters. Use k=9 x109 for the electric constant.A 10 nC charge generates an electric field within an isolated chamber. At a point a distance d meters away from the charge, the electric field is measured to be 4 N/C. Determine d in meters. Use k=9 x109 for the electric constant. (nC to C in final answer)A positive charge Q1 = 38.5 nC is located at the origin. A negative charge Q2 = -6.5 nC is located on the positive x-axis p = 19 cm from the origin. Calculate the location, x, on the x-axis, in centimeters, where the electric field is equal to zero.
- The electric field at a distance of 0.35 m from a very long line charge is 1250 N/C. Calculate the total charge in a 6.00-cm section of such line. Express your answer in nC.A point charge q = 2C is situated at a long distance r = 15 m on axis from one end of a thin no conducting rod of length L = 2m (r > L) having a charge Q = 7C (Uniformly distributed along its length). The magnitude of electric fied at the point charge q will feel is: Magnitude of the Electric field q will feel Give your answer up to at least three significance digits. V/mASAP
- An electric field of E = 34.97 MV/m is desired between two parallel plates, each of area 4.1 cm2 and separated by 14.19 mm of air. What charge must be on each plate? Express your answer in nC. Note: For this problem, use ε0 = 8.8541878x10-12 F/mA point charge q1 = 8.0 nC is at the origin and another point charge q2 = 12.0 nC is on the x-axis at X = 4.0 m. Find the electric field at (x=0 , y=3.0 m). Express oll numerical values in three significant figures. Calculate the electric field component due to each point charge. Fill out the table below. Express all numerical values in three significant figures. Do not forget to include the sign if the value is negative. E, (N/c) E, (N/c) electric field due to charge 1 E1 electric field due to charge 2 E2 net electric field From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is N/cA negative charge -Q and a positive charge +2Q are placed along the x-axis at x = 0.0 m and x = 1.0 m, respectively. At what position along the x-axis is the electric field equal to zero? Express your answer in meters, to at least one digit after the decimal point.