Suppose a gene has the sequence ATGGGTTATCGCGAGTAC. A point mutation changes the gene to read ATGGGTTATGCGGAGTAC. How would the polypeptide product of this gene change?
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Suppose a gene has the sequence ATGGGTTATCGCGAGTAC. A point mutation changes the gene to read ATGGGTTATGCGGAGTAC. How would the polypeptide product of this gene change?
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- A gene contains 141 codons. How many nucleotides are present in the gene’s coding sequence? How many amino acids are expected to be present in the polypeptide encoded by this gene?Consider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.Assume the first nucleotide in the sequence is at the +1 position. Transcribe the DNA sequence into mRNA and then translate it into the polypeptide. Give the polypeptide sequence in the following form: Met-Thr-Trp-Tyr-Val etc. 5' ACCGAAGGACTTATGGAGCGCTCATGATTTGCT 3'
- Given the following protein, which of the following sequences of TEMPLATE strand DNA would code for it? Pay attention to the polarity of the polypeptide and the strands of DNA that you choose. Use the codon chart to the right. AUG = met AAA = lys GCU = ala | CUU = leu ACU = thr -lys - thr - ala - leu - met (amino end) 5' TAC GAA CGA TGA TTT TAC ATT 3' 5' ATG CTT GCT ACT AAA ATG TAA 3' (carboxyl end) met 5' TAC TTT TGA CGA GAA TAC ATT 3¹' 3' TAC TTT TGA CGA GAA TAC ATT 5¹ 5' ATG AAA ACT GCT CTT ATG TAA 3¹ 3 TAC GAA CGA TGA TTT TAC ATT 5'(a) Write the complementary base sequence for the matching strand in the DNA section shown below:. 5’ – A T G T T A C T A G T C – 3’ (b) The following section of DNA is used to build an mRNA for a protein: 3′—AAG—CTT—CTC—5′. What is the corresponding mRNA sequence?The peptide hormone oxytocin induces labor by stimulating the concentration of uterine smooth muscle. Its amino acid sequence is as follows: Cys-Tyr-Ile-Gln-Asn-Cys-Pro-Leu-Gly.Write a messenger RNA sequence for that sequence. Write the sequence of the two strands of DNA nucleotides that carry the information. for that protein.
- Use the following DNA sequence, and write the resulting messenger RNA sequence TACTTTGAATGCGGCCGTATC?Assume the first nucleotide in the sequence is at the +1 position. Transcribe the DNA sequence into mRNA, and then translate it into the polypeptide. Give the polypeptide sequence in the following form: Met-Thr-Trp-Tyr-Val etc. 3' TCACAATACAAAGGTGTACTGATCTCATCTCCATAA 5'The amino acid glycine is encoded by four codons: GGA, GGC, GGG, and GGU. Which of the following statements correctly explains this fact? The glycine anticodon contains the sequence CC, but the 5' base of the anticodon can pair nonspecifically with the 3' base of the codon. The glycine anticodon contains the sequence CC, but the 3' base of the anticodon can pair nonspecifically with the 5' base of the codon. Glycine tRNA has four anticodons, and the appropriate anticodon specifically pairs with the correct codon. There are four tRNAs for glycine, each of which has an anticodon that specifically pairs with the correct codon. all of the above
- Suppose the codon sequence AUGACCCGGCUACUG has a single base pair mutation to AUGACCCGGUUACUG. If the old protein sequence was Met-Thr-Arg-Leu-Leu, what will be the new sequence encoded by the mutant gene?The genetic code consists of a series of three-base wordsthat each code for a given amino acid.(a) Using the selections from the genetic code shown below, de-termine the amino acid sequence coded by the following seg-ment of RNA: UCCACAGCCUAUAUGGCAAACUUGAAG AUG= methionine ;CCU= proline; CAU= histidine ;UGG= tryptophan AAG= lysine ; UAU= tyrosine ;GCC= alanine ;UUG= leucine ;CGG= arginine ;UGU= cysteine ;AAC =asparagine ;ACA=threonine ;UCC= serine ;GCA=alanine ;UCA=serine(b) What is the complementary DNA sequence from which this RNA sequence was made? (c) If you were sequencing the DNA fragment in part (b), how many complementary chain pieces would you obtain in the tube containing ddATP?Sickle cell disease is caused by a so-called “point mutation" in the human B-globin gene. A point mutation is the result of a single base substitution in the DNA encoding a gene. The sickle cell mutation results in substitution of Val for Glu at position 6 in the B-globin protein. (a) Using the information in Figure 5.18 explain how a point muta- tion could change a codon for Glu to a codon for Val. (b) Do you expect the pI for the sickle cell B-globin to be higher or lower than the pl for wild-type B-globin? Explain.