Use the graphical method to construct the shear-force and bending-moment diagrams for the beamshown. Let a=4.0 ft, b-8.0 ft, c-4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-forceand bending-moment diagrams on paper and use the results to answer the questions in the subsequentparts of this GO exercise.AaaBPart 2bdFor this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for thereactions are indicated by the directions of the red arrows shown on the free-body diagram below.(Note: Since Ax = 0, it has been omitted from the free-body diagram.)Save for LaterBWAnswers: Ay = i 37.575eTextbook and MediaWAV=P₂bCV₁ - V₁ = Sw(x) dxCCсD+Ddkips, Ey=M₂EiEZAxEyX IncorrectIf your answer for part (a) or (e) is incorrect, recall that concentrated loads creatediscontinuities in the shear-force diagram. Refer to the table below (Construction Rules forShear-Force and Bending-Moment Diagrams), Rule 1. At each concentrated load, the sheardiagram jumps by an amount equal to the concentrated load. The change in the diagram is inthe same direction as the force arrow. From the FBD, observe that the positive direction forthe reaction force is assumed to act upward at A. If your answer for part (b), (c), (d) or (f) isincorrect, recall that the change in the shear force between any two locations is equal to thearea under the load diagram w between those same two points. Refer to the table, Rule 2.Also, note that since the arrows shown for the distributed load w point upward, the areaunder the load diagram is taken as a positive area. Thus, the change in the shear-forcediagram is positive.Construction Rules for Shear-Force and Bending-Moment DiagramsEquationLoad Diagram wShear-Force Diagram VRule 1: Concentrated loads create discontinuities in the shear-force diagram.Positive jumpin shear force VPx56.925Attempts: 1 of 5 used Submit AnswerV₂% TaRule 2: The change in shear force is equal to the area under the distributed-load curve.Sw(x) dx-w(x)4-S"AV-V₂-V₁-w) deV₂Bending-Moment Diagram MSlope-V₁-MAkips.M₁"ASlope V₂30MaFaM₂

Answered: Image /qna-images/answer/b1b35602-825f-4875-8354-b7c8acd03a09.jpg

B |C E For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. Note: Since Ax = 0, it has been omitted from the free-body diagram.)

B |C E For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. Note: Since Ax = 0, it has been omitted from the free-body diagram.)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a=4.0 ft, b=8.0 ft, c=4.0 ft, d=3.0 ft, w = 6.5 kips/ft and P = 45 kips. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. A A a B a B W Answers: Ay = i b d For this loading, calculate the reaction forces Ay and Ey acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) W с b C C P C D P kips, Ey = d E i E X 'y x kips.
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Use the graphical method to construct the shear-force and bending-moment diagrams for the beam shown. Let a-3.0m, b-6.0 m, M₁-55 kN-m and Mc-85 kN-m. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. My Answers: A, A Calculate the reaction forces A, and D, acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since A, 0, it has been omitted from the free-body diagram.) 178.46 Mc eTextbook and Media Me KN, D,- 41.45 KN.