as an acceleration in the x-direction given by ax = 10.5t in./sec2. If the velocity of the particle in the x-direction is 8.5 in./sec when t = 0, lculate the magnitudes of the velocity v and acceleration a of the particle when t = 2.4 sec. Construct v and a in your solution. nswers: When t = 2.4 sec, = = i i in./sec in./sec²
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- The y-coordinate of a particle in curvilinear motion is given by y = 2.4t3 - 7.3t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 5.7t in./sec2. If the velocity of the particle in the x-direction is 13.9 in./sec whent = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 3.0 sec. Construct v and a in your solution. Answers: Whent= 3.0 sec, V = i in./sec i in./sec2 a =The y-coordinate of a particle in curvilinear motion is given by y = 12.6t³-13.8t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by a = 9.1t in./sec². If the velocity of the particle in the x-direction is 11.4 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 3.9 sec. Construct v and a in your solution. Answers: When t = 3.9 sec. v= in./sec in./sec²The y-coordinate of a particle in curvilinear motion is given by y = 7.5t3 -7.5t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by a, = 2.8t in./sec?. If the velocity of the particle in the x-direction is 5.3 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 1.6 sec. Construct v and a in your solution. Answers: When t = 1.6 sec, V = in./sec i in./sec? a =
- The x-coordinate of a particle in curvilinear motion is given by x = 5.3t³ - 2.2t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 5.5t. If the particle has y-components y = 0 and vy = 2.8 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 4.4 sec. Sketch the path for the first 4.4 seconds of motion, and show the velocity and acceleration vectors for t = 4.4 sec. Answers: V = a = i i ft/sec ft/sec²The x-coordinate of a particle in curvilinear motion is given by x = 5.6t3 - 2.7t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by a, = 3.9t. If the particle has y-components y = 0 and vy = 5.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 6.0 sec. Sketch the path for the first 6.0 seconds of motion, and show the velocity and acceleration vectors for t = 6.0 sec. Answers: V = i ft/sec i ft/sec? a =2. A particle moves along a straight line with the equation x=16t+4t2-3t3 where x is the distance in ft and t is the time in second. Compute the acceleration of the particle after 2 seconds?
- The position of a particle moving along the x axis is given in centimeters by x = 9.39 + 1.86 t°, where t is in seconds. Calculate (a) the average velocity during the time interval t = 2.00 s to t = 3.00 s; (b) the instantaneous velocity at t = 2.00 s; (c) the instantaneous velocity at t = 3.00 s; (d) the instantaneous velocity at t = 2.50 s; and (e) the instantaneous velocity when the particle is midway between its positions at t = 2.00 s and t = 3.00 s. (a) Number i Units (b) Number i Units (c) Number i Units (d) Number i Units (e) Number Units >Determine the acceleration of the particle moving in a circular path as shown below at the instant that its velocity is 1m/s while its tangential acceleration is 2m/s².9. A particle moves along a circular path of radius 300 mm. If its angular velocity is e=(2t^2 )rad/sec, where t is in seconds, determine the magnitude of the particle's acceleration and velocity when t = 2 sec. (a) Velocity 2.4 m/sec O 2.5 m/sec O 2.6 m/sec O 2.7 m/sec (b) Acceleration O 19.394 m/sec^2 O 19.934 m/sec^2 19.351 m/sec^2 O 19.349 m/sec^
- The position of a particle moving along the x axis is given in centimeters by x = 9.77 + 1.23 f, where t is in seconds. Calculate (a) the average velocity during the time interval t= 2.00 s to t = 3.00 s; (b) the instantaneous velocity at t = 2.00 s; (c) the instantaneous velocity at t = 3.00 s; (d) the instantaneous velocity at t = 2.50 s; and (e) the instantaneous velocity when the particle is midway between its positions at t = 2.00 s and t= 3.00 s. (a) Number Units (b) Number i Units (c) Number i Units (d) Number i Units (e) Number Units > >1. The velocity of a particle moving along a straight line is v = t³ + 3t m/s, where t is in seconds. If its position s=0. when t=0, determine its acceleration and position when t=3 seconds. 2. A particle moves in a straight line according to the law s = t¹ - 50t where s is in m and t in seconds. When t=6 seconds, compute the velocity. Find the average velocity during the 4th second.The curvilinear motion of a particle is defined by v= 50 16t and y = 100 - 4t2, where v, is in meters per second, y is in meters, and t is in seconds. It is also known that x = 0 when t = 0. Plot the path of the particle and determine its velocity and acceleration when the position y= 0 is reached.