An antelope is being pulled by two forces whose vector-component expressions are: F1 = 2.4Ni + -7.3Nj + -7.7Nk F2 = -2Ni + 1.2Nj + 4Nk What is the angle (in degrees) between these two vectors?
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- What is the y component of the vector (3i8k) m/s? (a) 3 m/s (b) 8 m/s (c) 0 (d) 8 m/s (e) none of those answersThe components of vectors ?⃗ and ?⃗ are given as follows: Ax = 5.1 Bx = -2.6 Ay = -5 By = -4.3 What is the magnitude of vector sum ? + ? choices: a. 2.5 b. 5.1 c. -9.3 d. 9.6 The equilibrant force is 5500 Dynes in magnitude and in the direction of 30 degrees South of East. Find the resultant force and direction. 5500 Dynes 170 degres 5500 Dynes, 150 degrees 5500 Dynes, 130 degrees 5500 Dynes, 30 degreesThe vector V3 of the figure is equal to: A. V2 - V1 B. V1 /cos θ C. V1 - V2 D. V1 + V2 E. V1 cos θ
- 2. Force vectors are given by equations F1 = 5i + 7j - 6k (kN) and F2 = -10k (kN). What is the direction of the resultant measured from the positive x-axis? Express your answer in unit of degrees.Find the x- and y-components of the vectors, C where C-A-B. Notice that we are subtracting the vectors. A B. -5 -4 -3 -2 -1 1 2 3 4 -3 -4 CACX-1, G-3 B. Cx-1, Gy=7 c x=7, Gy=1Q2a The resultant vector R= (F1 + F2) and acts on body P. The force vector F1 acts on body P with a magnitude of 172.80 N and the angle between Fl and the x-axis is 65°. If the magnitude of R is 258.25 N and the angle between the resultant (R) and the x-axis is 48°, determine the magnitude F2 if R = (F1 + F2). Assume coplanar vector forces and give your answer in Newtons (N) to 2 decimal places. F1 R F2 Body, P Answer:
- Based on the figure, express F1, F2, and F3 acting on the support in Cartesian form. Please express the answers in terms of unit vectors i and j. Round to three significant figures in the end.Vector A has a magnitude of 8 units and makes an angle of 45.0 degrees with the positive x-axis. Vector B also has a magnitude of 8 units and is directed along the negative x-axis. The magnitude of A-B is: 4V2 8 45° 4V7 Select one: A. 14.78 B. 4.65 C. 12.44 D. 8.22 E. NoneQuestion Four forces (measured in Newtons) act on a crate. The forces are given by the vectors: F₁ = 212i-136j + 241k N, F₂ = = 108i + 144j+ 189k N. F₂ = -400 + 180j + 240k N, and F₂ = -270€ N a) What is the resultant, R = F₁+F₂ + F3 + F4, of the four forces? What is the magnitude of the resultant force? b) If the displacement of the crate is given by d = 0.5i - 0.1j + 2.7k m What is the contribution by the first force F₁ to the work done, i.e. W = F₁. d? c) If the third force, F3, acts at the point (0.5, 0.8,0.1) m, what is the moment, M = r X F3, at the point (-0.5,0.8,0.7) m? d) What is the angle (in degrees to 2 decimal places) between the force vectors F₂ and F3? e) What is the force vector, F, that acts in the opposite direction to the force F₂ and has magnitude of 203 Newtons?
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