A well-known brokerage firm executive claimed that 50% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 51% of them said they are confident of meeting their goals Test the claim that the proportion of people who are confident is larger than 50% at the 0.01 significance level The null and alternative hypothesis would be: Но:р > 0.5 Но:р< 0.5 Но:р %— 0.5 Но:д < 0.5 Но:н > 0.5 Но:д — 0.5 Н:р< 0.5 Н:р> 0.5 Hi:p +0.5 H:д > 0.5 H:р < 0.5 Hi:д 2 0.5 The test is: two-tailed right-tailed left-tailed (to 3 decimals) The test statistic is: The p-value is: (to 4 decimals) Based on this we: Reject the null hypothesis Fail to reject the nul hypothesis
A well-known brokerage firm executive claimed that 50% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 51% of them said they are confident of meeting their goals Test the claim that the proportion of people who are confident is larger than 50% at the 0.01 significance level The null and alternative hypothesis would be: Но:р > 0.5 Но:р< 0.5 Но:р %— 0.5 Но:д < 0.5 Но:н > 0.5 Но:д — 0.5 Н:р< 0.5 Н:р> 0.5 Hi:p +0.5 H:д > 0.5 H:р < 0.5 Hi:д 2 0.5 The test is: two-tailed right-tailed left-tailed (to 3 decimals) The test statistic is: The p-value is: (to 4 decimals) Based on this we: Reject the null hypothesis Fail to reject the nul hypothesis
Chapter9: Sequences, Probability And Counting Theory
Section9.7: Probability
Problem 1SE: What term is used to express the likelihood of an event occurring? Are there restrictions on its...
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Transcribed Image Text:A well-known brokerage firm executive claimed that 50% of investors are currently confident of
meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week
period, found that in a sample of 100 people, 51% of them said they are confident of meeting their
goals
Test the claim that the proportion of people who are confident is larger than 50% at the 0.01
significance level
The null and alternative hypothesis would be:
Но:р > 0.5 Но:р< 0.5 Но:р %— 0.5 Но:д < 0.5 Но:н > 0.5 Но:д — 0.5
Н:р< 0.5 Н:р> 0.5 Hi:p +0.5 H:д > 0.5 H:р < 0.5 Hi:д 2 0.5
The test is:
two-tailed right-tailed left-tailed
(to 3 decimals)
The test statistic is:
The p-value is:
(to 4 decimals)
Based on this we:
Reject the null hypothesis
Fail to reject the nul hypothesis
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