A thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A light with wavelength λ = 325 nm goes in from the air to oil and water. a) Express the wavelength of the light in the oil, λ0, in terms of λ and n0. b) Express the minimum thickness of the film that will result in destructive interference, tmin, in terms of λ0. c) Express tmin in terms of λ and n0. d) Solve for the numerical value of tmin in nm.
A thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A light with wavelength λ = 325 nm goes in from the air to oil and water. a) Express the wavelength of the light in the oil, λ0, in terms of λ and n0. b) Express the minimum thickness of the film that will result in destructive interference, tmin, in terms of λ0. c) Express tmin in terms of λ and n0. d) Solve for the numerical value of tmin in nm.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter36: Applications Of The Wave Model
Section: Chapter Questions
Problem 15PQ
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A thin layer of oil with index of refraction no = 1.47 is floating above the water. The index of refraction of water is nw = 1.3. The index of refraction of air is na = 1. A
a) Express the wavelength of the light in the oil, λ0, in terms of λ and n0.
b) Express the minimum thickness of the film that will result in destructive interference, tmin, in terms of λ0.
c) Express tmin in terms of λ and n0.
d) Solve for the numerical value of tmin in nm.
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