A student performed an acid-base titration in the lab and recorded the results as shown below.Look very carefully at the results and answer the questions which follow.7.演定結果213.34627.400036終結摘定管讀數(cm)開始定管數(Cm所需演定州的積(cm)44標(a) Why do we perform acid-base titrations in our labs?(b) In the titration performed by the student, what was the net ionic equation for the chemical reactionoccurring?

Acid-base have an important quantitative aspect. It helps in determination of concentration of an…

A student performed an acid-base titration in the lab and recorded the results as shown below. Look very carefully at the results and answer the questions which follow. 7. HO. 演定結果 3. 3:46 27.40 00 4.40 36 終結滴定管護數(cm) 開始演定管 (cm 所需演定州的體積(cm) 0011 多 3 標 0.025/ a) Why do we perform acid-base titrations in our labs? b) In the titration performed by the student, what was the net ionic equation for the chemical reaction OCcurring?

A student performed an acid-base titration in the lab and recorded the results as shown below. Look very carefully at the results and answer the questions which follow. 7. HO. 演定結果 3. 3:46 27.40 00 4.40 36 終結滴定管護數(cm) 開始演定管 (cm 所需演定州的體積(cm) 0011 多 3 標 0.025/ a) Why do we perform acid-base titrations in our labs? b) In the titration performed by the student, what was the net ionic equation for the chemical reaction OCcurring?

Introductory Chemistry: An Active Learning Approach

6th Edition

ISBN:9781305079250

Author:Mark S. Cracolice, Ed Peters

Publisher:Mark S. Cracolice, Ed Peters

Chapter16: Solutions

Section: Chapter Questions

Problem 105E

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You want to determine the concentration of NaCl in a water. In preliminary analysis, it appears to be saline water with a NaCl content of approximately 4%. Should you dilute the sample if your titrant has a concentration of 0.1 M and you want to spend 25 mL of sample? Solution: You must dilute approximately ten times, taking 10 mL of sample and making up to 100 mL. In this way, 17.20 mL of titrant will be spent.
24 25 26 A chemistry student weighs out 0.0202 g of acrylic acid (HCH,CHCO,) into a 250. mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1800M NAOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Round your answer to 3 significant digits. mL x10 Continue Submit Assignment 2021 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility C 80 000 000 F1 F2 DII DD F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 @ 2$4 % &
In the titration calculation, moles of KOH were calculated from the known molarity and measured volume. Reaction stoichiometry was then used to convert that to moles of succinic acid. At this point, how could the moles of succinic acid be converted to a mass of succinic acid rather than a concentration?
Treatment of ammonia with phenol in the presence of hypochlorite yields indophenol, a blue product that absrobs light at 625 nm, which can be used for the spectrophotometric determination of ammonia. ocr -OH • NH, indophenol anion To determine the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water is mixed with 5 mL of phenol solution and 2 mL of sodium hypochlorite solution, and diluted to 25.0 mL in a volumetric flask. In sample B, 10.0 mL of lake water is mixed with 5 mL. of phenol solution, 2 mL of sodium hypochlorite solution, and 2.50 mL of a 5.50 x 10-4 M ammonia solution, and diluted to 25.0 mL. Sample C is a reagent blank. It contains 10.0 mL of distilled water, 5 mL of phenol solution, and 2 ml. of sodium hypochlorite solution, diluted to 25.0 mL. The absorbance of the three samples is then measured at 625 nm in a 1.00 cm cuvette. The results are shown in the table. Sample Absorbance (625 nm) A 0.374 В 0.621 0.045…
You want to determine the concentration of NaCl in a water. In preliminary analysis, it appears to be saline water with a NaCl content of approximately 4%. Should you dilute the sample if your titrant has a concentration of 0.1 M and you want to spend 25 mL of sample?
give a specific example of gravimetry analysis by enumerating the steps of the analysis
Suppose a group of students put 2.92 grams of an unknown solid acid into a 250-mL volumetric flask and filled it up to the mark with deionized water. After this they pipetted out 15.75 mL of a 1.78 M NaOH(aq) solution into another 250-mL volumetric flask and filled it up to the mark with deionized water. The students were given a pH meter that was already calibrated by their teaching assistant (T.A.) and they got the following result shown in the table below. Calculate the Molarity of the unknown solid acid. Hint: You can approximate the endpoint of the titration by taking the average volume between two consecutive titrant volume reading and you can assume that it is a 1:1 stoichiometry ratio between the acid and OH-(aq). VNaOH (mL) pH VNaOH (mL) pH 0 1.97 15 3.43 1 2.05 16 3.57 2 2.12 17 3.65 3 2.20 18 3.77 4 2.29 19 3.88 5 2.38 20 4.01 6 2.47 21 4.23 7 2.58 22 4.65 8 2.69 23…
A student performed titration to find the concentration of acetic acid. Titrant was sodium hydroxide. He went beyond the indicator color change by adding too much titrant. How will his experimental error affect the calculated value for the concentration of unknown acetic acid? calculated value actual value. calculated value < actual value calculated value = actual value. more information is necessary this is not a source of error
1. A sample of pure sodium oxalate, Na2C2O4 , weighing 0.2856 g is dissolved in water, sulfuric acid is added, and the solution titrated at 70°C , requiring 45.12 mL of a KMNO4 solution. The end point is overrun and back-titration is carried out with 1.74 mL of a 0.1032 N solution of oxalic acid. Calculate the normality of the KMNO4 solution. Hint: A redox reaction is involed between oxalate and permanganate. Look at the changes in oxidation state by determining the balanced redox reaction: 5C20,2 + + 2MN2+ 2 Mn04 + 10H* → 10CO2 + 8H20
You have a solution of a standardized titrant of 0.01254 M and a sample that approximately has a molarity of 0.48 M. What dilution do you have to do to spend approximately 15 mL of titrant if you have 25 mL and 10 mL pipettes to take the diluted sample and value it ? Solution: With the 10 mL pipette, the sample should only be previously diluted 1:25, with the 25 mL one 1:64. Therefore, 10 mL of the sample can be taken and made up to 250 mL.
Potassium permanganate (KMnO4) standard solution is prepared by dissolving 1.58 grams of potassium permanganate salt in 1.0 L of distilled water. Adjustment of this solution is done with sodium oxalate (Na2C2O4). 12 mL of this solution was spent in the titration of 0.0501 g sodium oxalate in acidic medium. Calculate the true molarity (M) of the potassium permanganate solution. 2MnO4 + 5C204²- +16H+. 2 Mn²+ +10 CO2 + 8 H2O
Potassium hydrogen phthalate, C8H5KO4 (molar mass 204.22 g mol-1) is a widely used standard for calibrating pH meters and carbon analyzers for performing chemical analyzes. I have a Dohrmann DC-80 carbon analyzer in my lab. The user manual calls for a standard of 400 mg / L (as carbon), in an aqueous solution. What is the mass percentage of carbon in this molecule?