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A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H:p> 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. (2) Test Ho : p= 0.55 against H.: p< 0.55. Use a = 0.05. test statisticz = critical z score The final conclusion is A. We can reject the null hypothesis that p = 0.55 and accept that p < 0.55. O B. There is not sufficient evidence to reject the null hypothesis that p == 0.55. (3) Test Ho : p= 0.6 against H.: p+ 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p + 0.6.

A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H:p> 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. (2) Test Ho : p= 0.55 against H.: p< 0.55. Use a = 0.05. test statisticz = critical z score The final conclusion is A. We can reject the null hypothesis that p = 0.55 and accept that p < 0.55. O B. There is not sufficient evidence to reject the null hypothesis that p == 0.55. (3) Test Ho : p= 0.6 against H.: p+ 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p + 0.6.

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H. : p > 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. %3D (2) Test Ho : p = 0.55 against H. : p < 0.55. Use a = 0.05. test statistic z = critical z score The final conclusion is A. We can reject the null hypothesis that p B. There is not sufficient evidence to reject the null hypothesis that p = 0.55. 0.55 and accept that p < 0.55. (3) Test Ho : p = 0.6 against Ha:p # 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p # 0.6.
Transcribed Image Text:A random sample of 90 observations is selected from a binomial population with unknown probability of success p. The computed value of p is 0.79. (1) Test Ho : p = 0.5 against H. : p > 0.5. Use a = 0.01. test statistic z = critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.5. O B. We can reject the null hypothesis that p = 0.5 and accept that p > 0.5. %3D (2) Test Ho : p = 0.55 against H. : p < 0.55. Use a = 0.05. test statistic z = critical z score The final conclusion is A. We can reject the null hypothesis that p B. There is not sufficient evidence to reject the null hypothesis that p = 0.55. 0.55 and accept that p < 0.55. (3) Test Ho : p = 0.6 against Ha:p # 0.6. Use a = 0.05. test statisticz = positive critical z score negative critical z score The final conclusion is A. There is not sufficient evidence to reject the null hypothesis that p = 0.6. B. We can reject the null hypothesis that p = 0.6 and accept that p # 0.6.
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