A gaseous mixture contain 32.9 mol % He, 40.7 mol % N2 and 26.4 mol % Determine the composition of this mixture on a mass basis based on the molecu weight given:
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- 4. Consider the mass% hydrogen peroxide experiment Catalase 2H,02(aq) 2H20(1) + 02(g) 3.00mL of a hydrogen peroxide solution is used in this experiment and 36.00mL of oxygen gas is trapped in the apparatus. The air temperature is 23.0°C. What is the mass% of H202 in the solution?the partial molar volumes of acetone and chloroform in a mixture in which the mole fraction of CHCl3 is 0.4693 are 74.166cm3/mol and 80.235 cm3/mol, respectively. What is the volume of a solution of mass 1.000 kg?Pressure (A) Explain the term pressure and state its S.I. unit. (B) Explain Henry’s law. (C)A bottle of H2 has just been received by the technicians in DkIT for use in the instrumentation lab. It is a 47 litre cylinder at a pressure of 50 atmospheres. The normal working pressures is 2 bar. (i) To what volume of gas will that equate at the working pressure? (ii) For how many hours will the gas last if it used at the rate of 0.5dm3 per hour? D)You see your best friend at the bar and you walk up behind her. You accidentally startle her and she takes a step backwards. Unfortunately, she is wearing high heels and her heels come down on your foot. She weighs only 55kg but the size of her heel is 6mm by 6mm.Determine the pressure that she applies on your foot. (E) If a diver dives to a depth of 35 m what will be: (i) the pressure in Pascals due the water column? (3 marks) (ii) the pressure of the air in…
- Given the following mixture of two compounds 10.00 mL of X (MW =50.00 g/mol)(density 1.160 g/mL) and 690.00 g of Y (89.00 g/mol))(density 1.282 g/mL), calculate the mole fraction of X.Determine the mole fraction of acetone in a 1.00 m solution of acetone (CH3COCH3) dissolved in ethanol (CH3CH3OH). The density of acetone is 0.788 g cm–3 and the density of ethanol is 0.789 g cm–3. Enter in decimal form (0.0111, 0.00220, 0.300 etc.)1. Calculate the volume of carbon dioxide adjusted to 25 °C and 1 atm, that plants need to make 1.00 g glucose, CóH12O6, by photosynthesis in the reaction 6CO2(g) + 6H20(I) C6H1206(s) + 602 (g).
- The partial molar volumes of two liquids A (M = 241.1 g mol) and B (M = 198.2 g mol1) in a mixture where XA = 0.375 are 188.2 cm³ mol and 176.14 cm mol, respectively. What is the volume of 1.500 kg %3D of this solution?What is the mole fraction of potassium permanganate, KMnO4, in an aqueous solution that contains 1.0049 g of potassium permanganate dissolved in 26.2858 grams of water? MW(KMnO4) = 158.034 g/mol.Prove that M = (mole IL) %3D is % x 10 x d M. M.wt
- The volume of a NaNO3 solution in 1000 g water at 25 °C and 1 atm can be described using the following equation: V/cm² = 1102.45 + 15.5236n+1.3877 +0.2149 where ne is the number of moles of NaNO3. (a) Calculate the partial molar volumes of NaNO3 and water at 1.5 m NaNO3. (b) Calculate the density of 1.5 m NaNO3 at 25 °C and 1 atm.Osmotic pressures are often reported in units of atmospheres or mm Hg. The latter impliesthat the height of a column of liquid can be used as a measure of pressure. This is, in fact, thebasis of the torricellian barometer from which the units of “torr” come. The pressure, P, isrelated to the height of the column by:P = ρghwhere ρ is the density of the liquid, g is the acceleration due to gravity and h is the height. Whatwill be the height (in mm) of a column of aqueous solution with a density of 0.9987 g/mL, if theosmotic pressure of the solution at 25 °C is 1.4 mm Hg? The density of mercury at thistemperature is 13.8 g/mL C6H12O6(aq)+ 2C2H5OH(aq)= 2CO2(g) Fermentation of 750 mL grape juice (density= 1.0g/L) is allowed to take place in a bottle with a total volume of 825 mL until 12% by volume is ethanol . Assuming that the CO2 is insoluble in H2O (actually, a wrong assumption), what would be the pressure of CO2 inside the wine bottle at 25 degrees Celcius? (The density of ethanol is 0.79g/L .)