A fatigue crack growth test is being carried out on a large steel plate containing a 2mm edge crack. The growth of cracks can be well represented by the Paris LawdaA(AK), where A is a constant (A = 6.6 × 10-13 (MPa)-4 m cycle-1) and AK =KmaxAN-=KminIf the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R=-0.25 (R= min/max) at a frequency of 2 Hz (2 cycles per second), how long will thecrack grow to after 10 hours?Note that:fai da = [₁1afand K for the edge crack is K= 1.12 σ√(ла)8 mm7.2 mm2.6 mm3 mm10 mm

The initial edge length is a1=2 mm The constant A is 6.6*10-13 (MPa) m cycle-1. The frequency is n=2…

A fatigue crack growth test is being carried out on a large steel plate containing a 2 mm edge crack. The growth of cracks can be well represented by the Paris Law da = A(AK), where A is a constant (A = 6.6 x 10-13 (MPa)-4 m cycle ¹) and AK = Kmax AN Kmirr - If the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R = -0.25 (R=0min/max) at a frequency of 2 Hz (2 cycles per second), how long will the crack grow to after 10 hours? Note that: ja; da = [1-4] af and K for the edge crack is K = 1.12 σ√(ла) 8 mm 7.2 mm 2.6 mm 3 mm 10 mm

A fatigue crack growth test is being carried out on a large steel plate containing a 2 mm edge crack. The growth of cracks can be well represented by the Paris Law da = A(AK), where A is a constant (A = 6.6 x 10-13 (MPa)-4 m cycle ¹) and AK = Kmax AN Kmirr - If the plate is subjected to a fatigue stress for which max = 120 MPa and a ratio R = -0.25 (R=0min/max) at a frequency of 2 Hz (2 cycles per second), how long will the crack grow to after 10 hours? Note that: ja; da = [1-4] af and K for the edge crack is K = 1.12 σ√(ла) 8 mm 7.2 mm 2.6 mm 3 mm 10 mm

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.5.1P: The rails of a railroad track are welded together at their ends (to form continuous rails and thus...

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