A disk of radius 2.25 m rotates about its axis. Points on the rim of the disk undergo tangential acceleration of magnitude 1.81 m/s². At a particular time, the rim has a tangential speed of 1.67 m/s. At a time 0.867 s later, what is the tangential speed v of a point on the rim, the magnitude of the point's radial acceleration a,, and the magnitude of its total acceleration hot? m/s a, = m/s? Atot = m/s²

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
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A disk of radius 2.25 m rotates about its axis. Points on the rim of the disk undergo tangential acceleration of magnitude
1.81 m/s?. At a particular time, the rim has a tangential speed of 1.67 m/s. At a time 0.867 s later, what is the tangential
speed v of a point on the rim, the magnitude of the point's radial acceleration a,, and the magnitude of its total acceleration
Arot?
U =
m/s
ar =
m/s?
Atot =
m/s?
Transcribed Image Text:A disk of radius 2.25 m rotates about its axis. Points on the rim of the disk undergo tangential acceleration of magnitude 1.81 m/s?. At a particular time, the rim has a tangential speed of 1.67 m/s. At a time 0.867 s later, what is the tangential speed v of a point on the rim, the magnitude of the point's radial acceleration a,, and the magnitude of its total acceleration Arot? U = m/s ar = m/s? Atot = m/s?
Expert Solution
Step 1

Given that,

The radius of disk, r = 2.25 m

The tangential acceleration of the rim of the disk, at=1.81 m/s2

The initial speed of the rim, u = 1.67 m/s

Time, t = 0.867s

 

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