A bronze alloy specimen having a diameter of 12.8 mm and a gage length of 50 mm was tested to fracture. Stress and strain dataobtained during the test are shown. Determine the fracture stress.Stress (MPa)5040-30-20-10-000Upper scaleO 59 MPaO 24 MPaO 40 MPaO 50 MPaO 33 MPa0.1000.005Lower scale0.2000.010Strain (mm/mm)0.3000.0150.4000.020

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Answered: A bronze alloy specimen having a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

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A tensile test specimen of stainless steel alloy having a diameter of 0.495 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the true fracture stress if the final diameter of the specimen at the location of the fracture was 0.350 in. Stress (ksi) 120 Upper scale Lower scale H 0.0 0.020 0.040 0.060 0.080 0.100 0.120 0.0 0.002 0.004 0.006 0.008 0.010 0.012 Strain (in./in.) 90 60 30 0- 300 ksi O 126 ksi EA O 237 ksi O 202 ksi O 261 ksi
The following curve is a result of a tensile test. The gauge length was 2 in, and the specimen diameter was 0.505 in The fracture area was round with a diameter of 0.391 in. Remember to com 20000 Force (pounds force) 15000 10000 5000 0 16. The yield strength is 0 0.2% O 80,000 pl O 12.000 p 060,000 pl 85,000 p 0.1 0.2 Extension (inch) 0.3 0.4
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
A tensile test specimen of stainless steel alloy having a diameter of 0.495 in. and a gage length of 2.00 in. was tested to fracture. Stress and strain data obtained during the test are shown. Determine the proportional limit. Stress (ksi) 40 30- 20 10- 0- 0.0 0.0 Upper scale 0.020 0.002 22 ksi O 15 ksi E 19 ksi O 10 ksi 13 ksi Lower scale- 0.040 0.060 0.080 0.100 0.004 0.006 0.008 0.010 Strain (in./in.) 0.120 0.012
Q2c) Listed in the table below is the tensile stress-strain data for different grades of steels. Utilizing the data given answer the three queries given below. Tensile Strain at Fracture Strength Strength Fracture Strength Modulus Material Yield Elastic (MPa) (MPa) (MPa) (GPa) А 410 1440 0.63 265 410 200 220 0.40 105 250 C 815 950 0.25 500 610 800 650 0.14 720 210 E Fractures before yielding 650 550 1) Which will experience the greatest percent reduction in area? Why? 2) Which is the strongest? Why? 3) Which is the stiffest? Why? B.
1 - A tensile test is carried out on a specimen of mild steel of gauge length 40 mm and diameter 7.42 mm. The results are: Load (kN) 10 17 25 30 34 37.5 38.5 36 Extension (mm) 0 0.05 0.08 0.11 0.14 0.20 0.40 0.60 0.90 At fracture the final length of the specimen is 40.90 mm. Plot the load/ extension graph and determine (a) The modulus of elasticity for mild steel, (b) The yield stress, (c) The ultimate tensile strength, (d) The percentage elongation 2 - An aluminum alloy specimen of gauge length 75 mm and of diameter 11.28 mm was subjected to a tensile test, with these results: Load (kN) 2.0 6.5 11.5 13.6 16.0 18.0 19.0 20.5 19.0 Extension (mm) 0 0.012 0.039 0.069 0.080 0.107 0.133 0.158 0.225 0.310 The specimen fractured at a load of 19.0 kN. Determine (a) the modulus of elasticity of the alloy, (b) The percentage elongation. (c) The ductility in term of reduction of area (d) Fracture stress (e) Tensile strength
a. Plot the stress strain diagram b. Find the modulus of elasticity, ultimate stress and fracture stress and explain each term. Define modulus of toughness and find the same for the above specimen. Load (kN) Elongation (mm) 11.1 31.9 0.0175 0.0600 37.8 0.1020 40.9 0.1650 43.6 53.4 62.3 64.5 0.2490 1.0160 3.0480 6.3500
1.9 (A). During a tensile test on a specimen the following results were obtained: Load (kN) 50 55 30 0.094 40 0.127 Extension (mm) Load (kN) Extension (mm) 15 0.05 70 5.08 75 7.62 Diameter of gauge length = 19 mm Diameter at fracture = 16.49 mm 80 12.7 0.157 82 16.0 1.778 80 19.05 60 2.79 Gauge length 100 mm Gauge length at fracture = 121 mm 65 3.81 70 22.9 Plot the complete load extension graph and the straight line portion to an enlarged scale. Hence determine: (a) the modulus of elasticity; (d) the nominal stress at fracture; (b) the percentage elongation; (e) the actual stress at fracture; (c) the percentage reduction in area; (f) the tensile strength. [116 GN/m²; 21%; 24.7%i 247 MN/m²; 328 MN/m2; 289 MN/m²]
1. Plot the engineering stress & strain diagram of an alloy having a tensile test result found in Table 1. The tensile test specimen has a diameter of 12.5mm and a gage length of 50.0mm. The given alloy is used to make a 30.0mm diameter cylinder, which is placed inside a hardened circular steel casement with a 30.01mm inner diameter. Table 1: Tensile test results of an alloy Change In Length (mm) Change In Diameter (mm) Load (kN) 0.000 0.0000 0.0000 4.364 0.0254 0.0019 -0.0057 13.092 0.0762 21.819 0.1270 0.0095 30.547 32.729 0.1778 0.7620 34.911 3.0480 30.01 mm O F Rigid Plate Cylindrical Alloy -Steel casement Figure k Section view of the steel casement encapsulating the cylindrical alloy 2. Determine the required minimum value of F such that the cylindrical alloy would touch the walls of the steel casement.
Q1- The following data was obtained tensile test ɔn a specimen of 10 mm diameter and gauge length Lo=50 mm: 0 38 | 76.2 92.7 107 149 160.4 | 155 142 124.7 load(KN) | elongation(mm) 0 0.02 0.12 0.25 0.50 2.03 3.55 4.06 5.1 5.84 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the (ay, ey), (ou , eu), (of,, ef), modulus of elasticity, then detected in the draw ((stroin hardening (m)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region))?
640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)
Review Data taken from a stress-strain test for a ceramic are No elements selected o(ksi) given in the table. The curve is linear between the origin and the first point. 50 40 30 Figure 1 of 1 20 10 σ (ksi) e (in./in.) ex 10-*(in./in.) 0.5 1.0 1.5 2.0 25 33.2 0.0006 45.5 0.0010 Press (ENTER to select this element. Press (ESc to return to the main menu. Press (CTRL+Q) to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022

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