A B C D E F - 2 m - -2 m -2 m- Hinge | 2m+ -2 m- -2 m- -2 m
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Draw the influence lines for the shear and bending moment at point F of the beam shown in this figure below
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- -55./Draw the influence line for the force in member CJ. then compute the maximum live force (tension or compression) that can be developed in this member due to a uniform live load of 3 kN/m which is transmitted to the *6-60. E DE of th force (te- member truss along the bottom cord. transmiQ4\ Which of the following is a zero-force member? 3 8KN 4 G 4 エ 子c D. 4 B AC BD IF IDsin (t – 1) lim t->1 t2 + 2t - 3
- De term ine the kin d and am ount of stress in e ach mem ber of the truss shown by the method of jo in ts in figure P 5-2 (page 76).- 1000lb 1000lb 1000lb 1000Ib 1000 Ib U. h = 20 ft 500lb 500 Ib L. L. RAV 6 pane ls at 10' - 6 ft RBy Note: 1. F o llo w strictly the lecture notes g iv en. Draw the FBD of e ach jo in t 2. Sum m a rize and tabu la te your answers. 3. Compu te the bar forces up to member U,L3 on ly because the truss lo a d in g is sym metric aland the bar forces of right sid e members are id en tic al w ith th e left s ide members. But you in c lu de th e rig ht sid e mem bers in have to the tabu la tion. 4. Show the com puta tio n ho w the leng th s were obta in ed. 5. Look for your own data in the table provided. 6. Copy the problem , data of problem and fig ure of the proble m TABULAT ION FOR SUMMAR Y OF COMPUTATION OF BAR FORCES METHOD OF JOINTS (PROBLEM P5-2 PAGE 76) Mem ber Identification Length Bar Forc e Туре of ft Ib force LOL1 10 3750 Tensio n L1L 2 10 Tension…(D² - 4D + 4)y =B Lsm +sm+sm-sm- Ax- Ra Rc- Ro= Hinge 90 kN/m 5m kN Ay KN kN kN Hinge -5m-5m KN
- Principle of superposition The beam is indeterminate to the first degree. Force in member BD is chosen as the redundant. This member is therefore sectioned to eliminate its capacity to sustain a force. 60 kN/m 3 m 1.8 m 60 45 actual structure (a) 160 kN/m B FaD redundant рrimary structure ARD FRp applied Fap D(D² - 4D +4)y= ex(c) The rigid bar ABC is suspended from three wires of the same material. The cross- sectional area of the wire at B is equal to half of the cross-sectional area of the wires at A and C. Determine the tension in each wire caused by the load P shown. ----|--²--| A 9 DAB T L P Fig. Q1(c) PL Hint: S = note that ABC is a rigid bar. EA C
- Determine the moment of the forces acting on the structure about point A. THIS IS AN EXAM. DO 90N DUPLICATE OR SI THIS IS AN EXAM. DONDUPLICATE OR SI THIS IS AN EXAM OR SI 50°OT DUPLICATE DUPI DO NOT DUPLI 2ON OR SH DO NOT B THIS IS AN EXAME DO NOT THIS IS A 0.7mm THIS IS AN EXAMA + THIS IS AN E EX 0.5m [CATE OR SH RICATE OR SI THIS IS AN THIS IS AN EXAM. UPLICATE OR SI ´HIS IS AN EXAM." DOI.OMT DUPLICATE OR SIA steel pipe (1) is attached to an aluminum pipe (2) at flange B. The pipes are attached to rigid supports at A and C, respectively 18 m 14 m Member (a) has a cross-sectional area A,-3,600 mm2, an elastic modul as a cross-sectional area A 3,600 mm2, an elastic modulus E-200 GPa, and an allowable has a cross-sectional area A2 2,o00 mm2, an elastie modulus E-70 GPa, and an allowable normal stress of 120 MPa. Determine the maximum load Pthat can be applied to fange B without exceeding either allowable stressNFD, SFD and BMD of the structure