A = [1 1; 1 -1]; b = [80; 20]; A_inverse = inv(A); x = A\b; disp('A inverse is'); disp(A_inverse); disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]); if isequal(round(x), [50; 30]) disp('Success'); else
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A = [1 1; 1 -1];
b = [80; 20];
A_inverse = inv(A);
x = A\b;
disp('A inverse is');
disp(A_inverse);
disp(['x1 is ', num2str(x(1)), ' and x2 is ', num2str(x(2))]);
if isequal(round(x), [50; 30])
disp('Success');
else
disp('Incorrect: Please try again');
end. Output matlab. .
Step by step
Solved in 3 steps with 1 images
- 4. A={3,4}, B={4,5}. An B= AUB= A-B= A OB= AXB=typedef struct { short data[4];} MatrixElement; void copy_matrix(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[i*COLS+j].data[k]; } } }} void copy_matrix_transpose(MatrixElement m1[], MatrixElement m2[], int ROWS, int COLS) { int i, j, k; for (i = 0; i < ROWS; i++) { for (j = 0; j < COLS; j++) { for (k = 0; k < 4; k++) { m1[i*COLS+j].data[k] = m2[j*ROWS+i].data[k]; } } }} You can assume the following conditions: The matrix m1 is allocated at memory address 0, and matrix m2 immediately follows it. Indices i, j, and k are kept in registers. ROWS and COLS are constants. The cache is initially empty before the function call. The cache is write-back (i.e., only writes back to memory when a line is…Hef sharks_minnows (minnows, sharks): shark_count = 0 minnow_count = len (minnows) for i in range(minnow_count): curr_shark_height = minnows [i] if curr_shark_height is not None: minnows [i] = None for j in range (i + 1, minnow_count): if minnows [j] == curr_shark_height: minnows [j] = None curr_shark_height -- 1 shark_count += 1 return shark_count <= sharks The provided code is imperfect, in that it sometimes returns True when it should return False, and sometimes returns False when it should return True. (a) Provide an example of a function call where the provided code will correctly return True (i.e. a True Positive) (b) Provide an example of a function call where the provided code will correctly return False (i.e. a True Negative) (c) Provide an example of a function call where the provided code will incorrectly return True (i.e. a False Positive) (d) Provide an example of a function call where the provided code will incorrectly return False (i.e. a False Negative)
- def strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?Debug Program3: int element(int arr[], int num) { in i, ele; ele = arr[0]; for (i = 1; i < num; i++) if (arr[i] > ele) ele = arr[i]; return ele; } main() { arr[] = {1, 24, 145, 20, 8, -101, 300}; int n = sizeof(arr)/sizeof(arr[0]); printf("element of array is %d", element(arr[], n)); } 24 145 -101 300 Program4: main() { int m,n; for(i 0; i << 5; i++) { printf("\t\t\t\t"); for(j 0; j << 5; j+++) printf("*"); printf("/n"); } Program 5: int func(int) main() { int num = 7, c; int f= func(num); printf("\n\n%d of %d\n\n", num, f); } int func(aj); { if(aj=1 aj=0) return 1; else return (aj*fun(aj-1); } 49 5040 7117 none of…Modify the given code to accept float instead of int as a coefficient in C LANGUAGE: // Node structure containing power and coefficient of// variablestruct Node {int coeff;int pow;struct Node* next;}; // Function to create new nodevoid create_node(int x, int y, struct Node** temp){struct Node *r, *z;z = *temp;if (z == NULL) {r = (struct Node*)malloc(sizeof(struct Node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}else {r->coeff = x;r->pow = y;r->next = (struct Node*)malloc(sizeof(struct Node));r = r->next;r->next = NULL;}} // Function Adding two polynomial numbersvoid polyadd(struct Node* poly1, struct Node* poly2,struct Node* poly){while (poly1->next && poly2->next) {// If power of 1st polynomial is greater then 2nd,// then store 1st as it is and move its pointerif (poly1->pow > poly2->pow) {poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 =…
- Regular expression to NFA to DFA conversion: Describes the process of taking a unique regular expression, converting that regular expression to an NFA, then converting the NFA into a DFA. Your regular expression must have at minimum two union, two concatenation, and two Kleene star operations. As followed, concatenations of single charaters can be condensed. Your regular expression cannot be a solved problem from any book. You should describe the regular expression with both processes to convert the regular expression to an NFA and the conversion of that NFA into a DFA.function myCompose(f,g){// TODO: return (f o g);// that is, a function that returns f(g(x)) when invoked on x.}İN C LANGUAGE Typedef struct Complex { Double a; Double b; } COMP_t, *COMP; write a function which finds and returns the position of the complex number whose absolute value is maximum in a two dimensional array of complex numbers.Absolute value of z=a+bi is |z|=(a^2+b^2)^1/2