A 0.1064-g of aldrin pesticide sample was decomposed and the liberated chloride was extracted using water. It was titrated with 23.28 mL of 0.03337 M AgNO3 using a chromate indicator. Express results in % aldrin (C12H8Cl6, MM=365).
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A 0.1064-g of aldrin pesticide sample was decomposed and the liberated chloride was extracted using water. It was titrated with 23.28 mL of 0.03337 M AgNO3 using a chromate indicator. Express results in % aldrin (C12H8Cl6, MM=365).
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- A mixture containing iodide is analyzed by the Volhard method. 0.6712 g of the sample is reacted with 50.00 mL of 0.05619 M AGNO3. The precipitate formed is removed by filtration and the excess Ag+ is back titrated with KSCN 0.05322 M, requiring 35.15 mL to reach the end point. Calculate the concentration of iodide in the sample in parts per million (mg/kg).A 2.345 g sample of an oat cereal is determined by a Kjeldahl analysis. The sample is digested with H₂SO4, the resulting solution made basic with 45% NaOH, and the NH3 distilled into 50.00 mL of 0.1150 M HCI. The excess HCI is back titrated using 29.30 mL of 0.140 M NaOH using mixed indicator (bromocresol green and methyl red). 1. If the protein in grains averages 15.50% w/w N, what is the % w/w protein in the sample? 2. Why is a mixed indicator used in nitrogen analysis? (Answer in 200 words or less.)The protein in a 1.2846-g sample of an oat cereal is determined by the Kjeldahl procedure for organic nitrogen. The sample is digested with H2SO4, the resulting solution made basic with NaOH, and the NH3 distilled into 50.00 mL of 0.09552 M HCl. The excess HCl is then back titrated using 37.84 mL of 0.05992 M NaOH. Given that the protein in grains averages 17.54% w/w N, report the %w/w protein in the sample of cereal.
- The arsenic in a 2.345g sample of a pesticide was converted to H 3 AsO4 by suitable treatment.The acid was then neutralized, and 60.00 ml of 0.06781M AgNO 3 was added to precipitate thearsenic quantitatively as Ag 3 AsO4. The excess Ag+ in the filtrate and washings from theprecipitate was titrated with 15.27 ml of 0.123 M KSCN; the reaction wasAg+ + SCN- → AgSCN(s)Calculate the percentage As 2 O 3 in the sample.A 0.1064-g of aldrin pesticide sample was decomposed and the liberated chloride was extracted using water. It was titrated with 23.28 mL of 0.03337 M AgNO 3 using a chromate indicator. Express results in % aldrin (C 12H 8Cl 6, MM=365). 63.21 % 22.12 % 17.28 % 44.42 %A sample containing calcium was analyzed by gravimetry, converting all calcium to calcium oxalate monohydrate (CaC2O4 • H2O). The sample weighing 0.2654 g was dissolved by adding 6M HCl, and then ammonium oxalate solution was added to precipitate all the calcium. The precipitate was suction filtered and dried in an oven at 95 °C for one hour. The solid obtained weighed 0.3216 grams.Calculate:A) The percentage of CaCO3B) The percentage of Ca C) The percentage of CaO
- The protein in a 0.2976 -g sample of cheese is determined by the Kjeldahl method. The sample is digested with H2SO4, the resulting solution made basic with NaOH, and the ammonia distilled into 50.00 mL of 0.09756 M HCl. The excess HCl is then back titrated using 39.87 mL of 0.05345 M NaOH. Calculate the % N and % protein of the sample.A 5.00 mL aqueous sample containing hydrogen peroxide was diluted to 25 mL and analyzed by titration with permanganate: 2MnO4- + 5H2O2 + 6H+ → 5O2 + 2Mn2+ + 8H2O The sample required 42.8 mL of 0.0175 M permanganate to reach the end point. What is the concentration of hydrogen peroxide in the original sample?A 0.1214-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.07011 M AgNO3, the sample was back titrated with 0.06021 M KSCN, requiring 27.15 mL to reach the end point. Calculate the purity of the Na2CO3 sample.
- A 0.4140-g sample of impure Na2CO3 (FW 105.99) was analyzed by the Volhard method. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back titrated with 0.05781 M KSCN, requiring 21.33 mL to reach the end point. What is the % purity of the Na2CO3sample?2.413 g sample contains Na2CO3, NaHCO3 and inert material. This sample was solved in water and diluted to 250.0 ml. 80 ml solution was taken and titrated with 0.09644 N HCl with the indicator of phenolftalein. 6.13 ml HCl was consumed. From a second solution, again 80 ml was taken and titrated with the same HCl solution with the indicator of methylorange. 15.4 ml HCl was consumed. Calculate the percentage of NaHCO3 and Na CO in sample (Na CO =106.0 g/mol, NaHCO =84.02 g/mol)A 2.00 mL sample of serum is analyzed for protein by the modified Kjeldahl method. The sample is digested and the resulting ammonia is distilled into a boric acid solution, consuming 15.0 mL of standard HCl to titrate the ammonium borate. HCl is standardized by treating 0.330 g of pure (NH₄)₂SO₄ in the same way. If 33.3 mL of acid is consumed in the standardization titration, what is the serum protein concentration in g% (wt/vol)?
