80 (5) (6) 70 (3) 60- 50 40- (1) 30 20 10- 0+ Strain
Q: After fracture, the total length was 53.086 mm and the diameter was 9.982 mm. Plot the engineering…
A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: Figure 7.31 depicts 6 possible Compact Tension specimens cut from the same rolled plate. Identify…
A: Consider the following directions in the given diagram:
Q: The following picture shows Charpy fracture surfaces of a material with different initial…
A: Introduction - The Charpy impact test is a maximum strain test that includes hitting a standard…
Q: A shows minor or no yielding before failure. is dimensionless, and the range is between 0 and 0.5.…
A: Above given fillups
Q: The specimen shown is made from a 25 mm diameter cylindrical steel rod with two 38 mm outer-diameter…
A:
Q: A steel plate is bent into a circular arc of radius 10 m. If the plate section be 120 mm wide and 20…
A: Given data: Radius, R = 10 m E=2×105 Nmm2 Area, A=120×10 mm2 y=10
Q: difference between the stress distribution of these two- equations ab a distance r= 0.02 a ahead of…
A:
Q: Problem 4: A tensile test is carried out on a bar of a mild steel of diameter 2 cm. the bar yields…
A: Question is based on the tensile test which is performed on mild steel bar .Diameter of mild steel…
Q: The deformation on the given plate is shown with dotted lines. Average normal unit strain in the BD…
A: Given above diagram we have to find average shear strain along BD and shear strain at B
Q: A steel bolt 0.003 m2 in cross- section is subjected to a static mean load of 178 kN.Using Soderberg…
A: Given: The cross-sectional area of the bolt is 0.003 m2. The static mean load is 178 kN. The yield…
Q: Problem 1.4. A tensile test was conducted on a mild steel bar. The following data was obtained from…
A:
Q: A 4340 steel plate containing an interior crack that is 2cm long, 10cm wide, and 0.5 cm thick. The…
A:
Q: A material containing cracks of initial length 0.010 mm is subjected to alternating tensile stresses…
A: Given:- Initial length =0.010mm tensile stress=25 and 125MPa number of cycles=350,000 alternating…
Q: What is the type of cup and cone fracture? a. Fatigue fracture b. Brittle fracture c. Ductile…
A: cup and cone fracture:
Q: As is shown in the Fig. 2, prove that there is no stress at all at the apex A (or a re-entrant,…
A: Resolving the forces N1 and N2 in the x and y direction - In x-direction - N1Cosα1andN2Cosα2 In…
Q: Problem 1.4. A tensile test was conducted on a mild steel bar. The following data was obtained from…
A:
Q: A 13 mm-diameter tensile specimen has a 50 mm gage length. The load corresponding to the 0.2 percent…
A: Given Data, Intial diameter of the specimen, do= 13 mmInitial gage length of the specimen, lo=50…
Q: A 12.5-mm round structural steel rod is loaded in tension to fracture. The 200-mm gage length of…
A: ASKED: To compute the average strain for the steel rod. Given, Gage length of the rod (L) = 200 mm…
Q: A three-point bending test was performed on an aluminum oxide specimen having a circular cross…
A:
Q: The ideal diameter of a steel tensile test specimen is O 1in O 2 in O 1/2 in • 1/4 in Question 2 How…
A: @1.The ideal diameter of a steel tensile test specimen is 1/2 in or 12.5mm Diameter doesn't effect…
Q: DWrite at least three critical conditions that should be combined to provide brittle fracture." poin
A: Brittle failure in material occurs generally due to : 1) When the stresses go lower than the yield…
Q: For a metal rod of 12 mm diameter and 22 cm length; a) When exposed to a load 2000 kg, it elongated…
A: Finding out true stress and strain and Poisson ratio.
Q: iv) If the specimen is loaded to a stress of 65 MPa and then unloaded, determine the residual…
A: From the figure, ( up to proportionality limit) σy=50 MPa∈y=0.002 Young's Modulus,…
Q: Sketch the stress-strain curve of the following tension test??? In the tension test of a metal…
A: this test in conducted in uniform tension machine. standardization of this test is follow by…
Q: In the tensile stress-strain curve below, label the following: elastic stage, plastic stage, necking…
A: Solution: The stress-strain graph has different points or region as follows: Proportional limit…
Q: I. Problem Solving: Answer what is being required. Show you complete solution. 1. Compute the…
A:
Q: Q2/ A tensile test specimen has a gage length 50 mm and its cross- sectional area = 100 mm2. The…
A: Solution; Given Data; Gauge Length (Lo)=50 mm Fmax=87000 NCross-sectional (Ao)=100 mm2…
Q: ".If the diameter of circular bar is (15mm) while the diameter of the bar at the section where…
A:
Q: 1) The cross section (hollow) of reinforced concrete beam is in the form of an outer square with a…
A: Below written equations used to find the bending moment at crack: (M/ I) = ( f/y) Here M is the…
Q: A specimen of a 4340 steel alloy having a plane strain fracture toughness of 45 MPa/m is exposed to…
A:
Q: 2- What is the largest size (mm) internal through crack that a thick plate of aluminium alloy…
A: aFor three quarters of yield stess:σf=34σy=34495=371.25Mpaso,Using…
Q: Problem 1.4. A tensile test was conducted on a mild steel bar. The following data was Stained from…
A:
Q: A very large, steel plate of yield stress 200 MPa has a crack at the centre of length 18 mm,…
A: Solution:-The given values are as follows,Yield stress σys=200MPaγ=0.3Centre…
Q: A cylindrical steel pressure vessel 500 mm in diameter with a wall thickness of 25 mm, is subjected…
A: Diameter (D) =500mm Thickness (t) =25mm Pressure (P) =6.5MN/m2
Q: DURING THE STRESS-STRAIN TEST, THE UNIT DEFORMATION AT A STRESS OF 30 MPa WAS OBSERVED TO BE 110 x…
A:
Q: In a standard tensile test, an aluminum rod of 20-mm diameter is subjected to a tension force of P-…
A: Given - Aluminum rod of diameter = 20mm Tension force = 30KN E = 70 Gpa Change in dia of rod =…
Q: 2. Shown below are pieces of unsaid material. They are combined and locked in each other and a force…
A:
Q: A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450…
A: Concept: The internal crack occurs when the overheating is very fast because of surface unequal…
Q: Is the fracture in the picture below brittle or ductile? Where is the location of the initiation of…
A: Solution: Ductile fracture is the one, where the specimen undergoes yielding and passes through its…
Q: The following uniaxial tensile testing data were collected from a ductile cast iron test specimen of…
A:
Q: Problem 1.4. A tensile test was conducted on a mild steel bar. The following data was obtained from…
A: “Since you have posted a question with multiple sub-parts, we will solve the first three subparts…
Q: In a bending test for a brittle material, the distance between the supports is 300mm, the cross…
A: GivenF=1000Kg=9810NCross Sectional Area=1200mm2t=30mmAssumeb=40mm
Q: A 13 mm diameter tensile specimen has 50 mm gauge length. If the load corresponding to the 0.2%…
A: Given data- Dia d=13 mm,Length L=50 mm,load for 0.2% offset=6800 kg. To Find- The yield stress.
Q: A 5 mm thick hollow steel rectangular tube must carry a tensile load of 200 kN. If the stress is…
A: Given:- Thickness of hollow rectangular section = 5 mm Tensile load of = 200 KN limited stress = 100…
Q: SITUATION. Given a trapezoidal beam with width at the top of 300mm and width at the bottom of 500mm…
A: To Determine Cracking moment in kN-m
Q: During the stress strain test, the unit deformation at a stress of 35 MN/m2 it was 667 x 10^-6 mm.…
A: Hook's law states that the stress is directly proportional to the strain up to the proportionality…
Q: What is the maximum stress that can be safely applied to a steel bar which contains a circular…
A:
For the stress-strain diagram, which region or point represents fracture?
Step by step
Solved in 2 steps
- 13- is defined as deformations not only cause line segments to elongate or contract, but they also cause them to change direction. A)Normal Strain B) Normal Stress C) Shear strain The normal strains cause a change in --- B) shape The shear strains cause a change in its shape. 14- A)Direction C) volume 15- C) volume -- by dividing the applied load P by the A)Direction We can determine the --- specimen's original cross-sectional area Ap. A)engineering stress B) True stress B) shape 16- C) Engineering strain D) True strain 17- is found directly from the strain gauge reading, or by ------------- dividing the change in the specimen's gauge length, 8, by the specimen's original gauge length Lo. A)Engineering stress B) True stress C) Engineering strain D) True strain 18- Any material that can be subjected to large strains before it fractures is called a---------- A)Brittle material B) Soft material C) Ductile material2- What is the largest size (mm) internal through crack that a thick plate of aluminium alloy 7075-T651 can support at an applied stress of (a) three-quarters of the yield strength and (b) one-half of the yield strength? Assume Y = 1. for 7075-T651, KỊC = 24.2 MPa ym and oYS = 495 MPa.B- Match the items from list A with the suitable ones from list B: A B 1 In a principal stress plot the Griffith a criterion is the crack will grow and the failure process is initiated. 2 b the ratio between the uniaxial A special feature for the Mohr- Coulomb criterion, compressive strength and the tensile strength is (8). 3 с When the tensile stress at the tip of the crack exceeds a certain value characteristic of the material depends on the normal stress acting over the failure plane 4 d The principal stress plot of the Griffith criterion, the orientation of the failure plane is independent of the confining stress. 5 e The critical shear stress (Tmax) for which shear failure occurs, represented by a parabola ending in a straight line
- A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture toughness of 77.0 MPa Vm (70.1 ksi Vin.) and a yield str- ength of 1400 MPa (205.000 si) The flaw size resolution limit of the fla.. tection appara- tus is 4.0 mm (0.16 in ) If the design stress is one-half of the yield strength and the value of Y is 1.0, determine whether a critical flaw foI this plate is subject to detection. Y MDThe specimen shown is made from a 25 mm diameter cylindrical steel rod with two 38 mm outer-diameter sleeves bonded to the rod as shown. Knowing that E = 200 GPa, determine (a) the load P so that the total deformation is 0.05 mm, (b) the corresponding deformation of the central portion BC. 38 mm diameter P' 25 mm diameter B 38 mm diameter C 50 mm 75 mm 50 mmA component made of Aluminium 6061-T651 has an edge crack with length equal to 15 mm, as shown The yield stress of the material is oy = 280 MPa and its fracture toughness (Kic) ranges from 40 MN/m3/2 to 60 MN/m³/2 Consider now the same edge crack in a semi-infinite plate. Determine the critical stress to avoid fracture. P I I I I ← 15 mm P↓ 100 mm 30 mm
- The thin square plate shown is uniformly deformed such that E - +1425 µE, E, - -668 uE, and ygy - +1125 prad. Determine the normal strain &, in the plate. 60 mm O -255 uE O -233 uE O -202 uE Ο -220 με O -184 uE2. The Goodman diagram relates oa and om for fatigue failure after a specific number of cycles N₁, where da is the cyclic stress amplitude, and on the mean stress. For a steel specimen it is found that a = a (0). [1- (om/OTS)] where GTS is the metal's tensile stress (375MPa), and oa (0)~0.450TS is the 107 cycle fatigue limit at zero mean stress. Assuming the specimen is cycled repeatedly between 0 stress and a peak stress, what is the maximum peak stress if failure in < 107 cycles is to be avoided? Ans: 233 MPaProblem 4: A tensile test is carried out on a bar of a mild steel of diameter 2 cm. the bar yields under a load of 150 kN and breaks finally at a load of 70 kN. Estimate; 1-the tensile stress at the yield point 2-the ultimate tensile stress 3-the average stress at the breaking point, if the diameter of the fractured neck is 1 сm.
- The principal stresses at a point are 20 (tensile) and o (compressive), and the stress at elastic limit for the material in simple tension is 210 N/ mm². According to maximum shear strain theory, the value of oat failure is (a) 70 N/mm² (c) 140 N/mm² (b) 105 N/mm² (d) 210 N/mm²2. The Goodman diagram relates oa and om for fatigue failure after a specific number of cycles Nf, where da is the cyclic stress amplitude, and om the mean stress. For a steel specimen it is found that oa oa (0). [1- (om/OTS)] where Ors is the metal's tensile stress (375MPa), and oa (0)~0.450TS is the 107 cycle fatigue limit at zero mean stress. Assuming the specimen is cycled repeatedly between 0 stress and a peak stress, what is the maximum peak stress if failure in < 107 cycles is to be avoided? Ans: 233 MPaWhich of the following statements regarding brittle failure and crack propagation is CORRECT? Elastic energy is consumed when a crack propagates, due to unloading of a volume of material. Energy is released when the surface area of a material increases, as a result of crack propagation. O The stress at the tip of a crack is less than the nominal stress (force over the cross-sectional area of the component) because the stress flows around the defect. O The fracture toughness of a material is its resistance to an increase in the radius of curvature of a crack. O A material will fail in brittle fashion when the stress intensity at the crack tip is greater than the fracture toughness of the material.