3.1 If the rate of wastewater generation is 150 gpcd, for a home with 4 persons, what is the minimum size of septic tank needed to treat its wastewater? a) 325 ft³ b) 625 ft³ c) 152 ft³ d) 161 ft³ 3.2 If the measured air pollution with CO is 90 mg/m³, what is the concentration in ppm in standard temperature 25 °C. a) 79 ppm b) 89 ppm d) 251 ppm c) 141 ppm
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- Q2: A municipal wastewater treatment plant discharges secondary effluent to a river. The worst condition occurs in the summer when the treated wastewater in summer is found to have a maximum flow rate of 10000 m³/day, a BODs of 30 mg/L, dissolved oxygen concentration of 1.5 mg/L and temperature of 25°C. At upstream of the disposal point the minimum flow in the stream is 0.65 m³/sec with BODs of 3.0 mg/L, dissolved oxygen concentration of 7.0 mg/L and temperature of 22°C. The mixing of wastewater and stream is almost instantaneous at the point of disposal and velocity of the mixture is 0.2 m/sec. The reaeration constant is estimated to be 0.4 per day at 20°C the dissolved oxygen sag curve a (100-km) (D20,40,50,75,100) temperature. Determine and sketch reach of the stream below the discharge?. DoQUESTION: An aerated lagoon wastewater treatment is to be designed for a municipal wastewater. The design population is 5000 persons, and the aerated lagoon is to provide secondary treatment. Pertinent data are: flow = 380 L/cap-d, influent BOD5 = 255 mg/L; effluent BOD5 = 20 mg/L, K = 2.18 d-1 oxygen required 1.6 kg O2/kg BOD5 applied to the lagoons, and the primary clarifier removes 33 % of the influent BOD5. Calculate the total lagoon volume (m3)Problem: 1. Design a facultative pond to treat (10650)gpm of sewage having (10650/20)mg/L of BOD. The average summer and winter temperature is 43°C and 13°C, respectively. Convert the same pond into aerated lagoon, if the concentration of influent BOD reaches to (10650)mg/L. 2. Determine the diameter of a trickling filter for a wastewater flowing at the rate of (10650)m³/day. The influent BOD (S.) concentration for the wastewater is (10650 * 10)mg/L, whereas desirable effluent BOD should be as per NEQS.
- Question 4. An industrial process produces a by-product compound ‘X’ which exceeds the sewer use limit. Therefore, before the wastewater can be discharged to the sewer, the concentration of ‘X’ must be reduced to below 30 mg C/L. The industrial wastewater, with a concentration of 1780 mg C/L, flows through a long series of channels before reaching the treatment reactor. The long series of channels can be modelled as a PFR with a volume of 23 m3 and the treatment reactor can be modelled as a CSTR with a volume of 15 m3. The compound ‘X’ naturally degrades in the series of channels before the treatment reactor with a reaction rate constant of 0.75 mg/(L·min). In the treatment reactor the addition of chemicals and catalysts cause compound ‘X’ to degrade according to second order kinetics described with a reaction rate constant of 0.015 L/(mg·min). a) Derive the appropriate HRT equations for the PFR channels and the CSTR treatment reactor (state all assumptions and show all work). b) Does…A domestic wastewater with BOD5 of 205 mg/L is treated by a secondary treatment plant that removes 85% of the BOD. You are to run a five-day BOD test with a standard 300-ml bottle on the treated sewage without seed. Assume the initial DO is 9.2 mg/L. (a) (b) What maximum volume of treated sewage should you put in the bottle if you want to have at least 2.0 mg/L of DO at the end of the test (filling the rest of the bottle with water)? If you make the mixture half water and half treated sewage, what DO would you expect after five days?i). A town produces 8 million litre of sewage per day. BOD of sewage is 260 mg/L, it is to be discharged into a river flowing at a rate of 0.2 m³/s and it's BOD is 5 mg/L. Find out the BOD of river after mixing? [Assume mixing is instantaneous]
- Design an activated sludge system for the wastewater flowing at the average rate of (10650)GPM having (10650/500)mg-BOD/L. Also determine the amount of air (m3/min), power (kW) and major nutrients (kg/day) required by the process for 80% BOD removal. Assume any missing data. Subject: environmental engineering 2As an operator of a wastewater treatment facility, you have learned that your plant runs well at an SRT (based on MLVSS (X) in the aeration basin) of 12 days. If today’s MLVSS (X) concentration is 2,700 mg/L and the RAS (Xr) concentration is 5,500 mg/L, how many L of sludge should you waste from the secondary clarifier today? Other design conditions: Average influent flow = 12,000 m3/d Influent soluble BOD = 150 mg/L Required effluent TSS = 30 mg/L Aeration tank Volume = 1,000 m3Please calculate the theoretical OD, COD, and ultimate BOD of a wastewater containing (a) 500 mg/L acetate (CH3COOH), which is fully biodegradable; or (b) 500 mg/L oil (C40H80), which is not biodegradable.
- 5.a. Why is it important to remove oil and grease, and settleable solids from wastewater before the biological wastewater treatment process?b.The wastewater from a manufacturing treatment plant is discharged to a municipal `treatment plant for processing with domestic wastewater. The characteristics of the wastewater from the manufacturing treatment plant are 3500 mg/l BOD, 4500 mg/l SS, 70 mg/l nitrogen and 2 mg/l phosphorous. The characteristics of the domestic wastewater are 350 mg/l BOD, 285 mg/l SS, 50 mg/l N and 11 mg/l P. If the required BOD/N/P weight ratio is 100/5/1, what is the minimum quantity of domestic wastewater required per 1000 gallons of manufacturing wastewater to provide adequate nutrients for biological treatment and the concentration of SS in the combined wastewater? c.What additional of NH4OH and H3PO4 would be required in pounds per million gallons of wastewater to provide the necessary nutrient levels for the treatment of the manufacturing wastewater described…Assume that DLSUD lake is 100m2 and its average height is 5ft. Wastewater that flows into the lake are the following: Food square kitchen waste 7 m3/sec; Total Dissolved Solids (TDS) is 25,000 mg/L which operates 8hrs per day CIH 5m3 /hr kitchen waste; TDS is 20mg/L which operates 4hrs per day PCH 20m3 /day diluted laboratory waste ; TDS = 40mg/L (1)Determine the volumetric flow rate of the lake water can still accommodate prior to rainfall.Determine how much extra volume is needed to treat the following wastewater in a CSTR than in a plug flow reactor. • Influent TOC: 273 mg/L • Required Effluent TOC: 57.0 mg/L • Flow: 792,500 gallons/day • First Order Microbiological Rate Coefficient (k’): 5.98/day Answer: 295,000 gallons 2. Discuss in detail at least two ways the k’ value may have been obtained and which technique is probably more accurate?